[英]How I parse Color java class to JSON with Jackson?
我正在嘗試使用Jackson
從JSON
反序列化Color
類,但它引發異常:
com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException:無法識別的字段“colorSpace”(java.awt.Color 類),未標記為可忽略。
我在做什么錯? 這是我的代碼:
File act = new File(new File().getAbsolutePath());
ObjectMapper om = new ObjectMapper();
File f = new File(act, "123.JSON");
om.writeValue(f, new person());
person per = om.readValue(f, person.class);
System.out.println(per);
這是我的個人課程:
public class person implements Serializable {
//it include getters, setters and builder
String nombe = "Pepe";
String CI = "12345678978";
Color c = Color.red;
}
java.awt.Color
類不是常規的POJO
或Enum
。 如果要將其存儲為JSON
格式,則需要實現自定義序列化器和反序列化器。 Color
類可以用它的RGB
表示來表示,你可以將它存儲為一個數字:
class ColorJsonSerializer extends JsonSerializer<Color> {
@Override
public void serialize(Color value, JsonGenerator gen, SerializerProvider serializers) throws IOException {
if (value == null) {
gen.writeNull();
return;
}
gen.writeNumber(value.getRGB());
}
}
class ColorJsonDeserializer extends JsonDeserializer<Color> {
@Override
public Color deserialize(JsonParser p, DeserializationContext ctxt) throws IOException {
return new Color(p.getValueAsInt());
}
}
簡單用法:
import com.fasterxml.jackson.core.JsonGenerator;
import com.fasterxml.jackson.core.JsonParser;
import com.fasterxml.jackson.databind.DeserializationContext;
import com.fasterxml.jackson.databind.JsonDeserializer;
import com.fasterxml.jackson.databind.JsonSerializer;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.databind.SerializerProvider;
import com.fasterxml.jackson.databind.module.SimpleModule;
import java.awt.*;
import java.io.IOException;
public class JsonPathApp {
public static void main(String[] args) throws Exception {
SimpleModule awtModule = new SimpleModule("AWT Module");
awtModule.addSerializer(Color.class, new ColorJsonSerializer());
awtModule.addDeserializer(Color.class, new ColorJsonDeserializer());
ObjectMapper mapper = new ObjectMapper();
mapper.registerModule(awtModule);
String json = mapper.writeValueAsString(new Person());
System.out.println(json);
System.out.println(mapper.readValue(json, Person.class));
}
}
上面的代碼打印:
{"nombe":"Pepe","c":-65536,"ci":"12345678978"}
Person{nombe='Pepe', CI='12345678978', c=java.awt.Color[r=255,g=0,b=0]}
看一下Color
存儲為JSON
對象的類似問題:
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