[英]Elastic Search composite grouping with range
考慮以下文檔在我的彈性搜索中。 我想根據排名對文檔進行分組,但是任何低於 1000 的排名都必須單獨顯示,並且必須對高於 1000 的任何排名進行分組我如何使用復合聚合來實現這一點,我是新手,我正在使用復合,因為我想使用 after允許分頁的關鍵功能。
Documents
{
rank : 200,
name:abcd,
score1 :100,
score2:200
},
{
rank 300,
name:abcd,
score1:100,
score2:200
}
Expected Result:
{
key:{
rank:101
},
doc_count:1,
_score1: {value:3123}
_score2 : {value :3323}
}
{
key:{
rank:1000-*
},
doc_count:1,
_score1: {value:3123}
_score2 : {value :3323}
},
{
key:{
rank:300
},
doc_count:1,
_score1: {value:3123}
_score2 : {value :3323}
}
######## QUery that I tried
{
"query":{"match_all":{}},
"aggs":{
"_scores":{
"composite"{
"sources":[
{"_rank":{"terms":{"field":"rank"}}}
]
}
},
"aggs":{
"_ranks":{
"field":"rank:[
{"to":1000},
{"from":1000}
]
}
"_score1": {"sum": {"field": "score1"}}
"_score2": {"sum": {"field": "score2"}}
}
}
}
據我了解,你想
1000-*
桶中_score1
的總和_score2
之和對於這種情況,您可以簡單地使用我在下面的答案中提到的術語聚合。
我已經提到了示例映射、示例文檔、查詢和響應,這樣您就可以清楚地了解正在發生的事情。
PUT my_sample_index
{
"mappings": {
"properties": {
"rank":{
"type": "integer"
},
"name":{
"type": "keyword"
},
"_score1": {
"type":"integer"
},
"_score2":{
"type": "integer"
}
}
}
}
POST my_sample_index/_doc/1
{
"rank": 100,
"name": "john",
"_score1": 100,
"_score2": 100
}
POST my_sample_index/_doc/2
{
"rank": 1001, <--- Rank > 1000
"name": "constantine",
"_score1": 200,
"_score2": 200
}
POST my_sample_index/_doc/3
{
"rank": 200,
"name": "bruce",
"_score1": 100,
"_score2": 100
}
POST my_sample_index/_doc/4
{
"rank": 2001, <--- Rank > 1000
"name": "arthur",
"_score1": 200,
"_score2": 200
}
POST my_sample_index/_search
{
"size":0,
"aggs": {
"_score": {
"terms": {
"script": {
"source": """
if(doc['rank'].value < 1000){
return doc['rank'];
}else
return '1000-*';
"""
}
},
"aggs":{
"_score1_sum":{
"sum": {
"field": "_score1"
}
},
"_score2_sum":{
"sum":{
"field": "_score2"
}
}
}
}
}
}
請注意,我在腳本中通過邏輯提到的地方使用了腳本化術語聚合。 一旦你經歷了它,我相信邏輯是不言自明的。
{
"took" : 5,
"timed_out" : false,
"_shards" : {
"total" : 1,
"successful" : 1,
"skipped" : 0,
"failed" : 0
},
"hits" : {
"total" : {
"value" : 4,
"relation" : "eq"
},
"max_score" : null,
"hits" : [ ]
},
"aggregations" : {
"_score" : {
"doc_count_error_upper_bound" : 0,
"sum_other_doc_count" : 0,
"buckets" : [
{
"key" : "1000-*", <---- Note this
"doc_count" : 2, <---- Note this
"_score2_sum" : {
"value" : 400.0
},
"_score1_sum" : {
"value" : 400.0
}
},
{
"key" : "100",
"doc_count" : 1,
"_score2_sum" : {
"value" : 100.0
},
"_score1_sum" : {
"value" : 100.0
}
},
{
"key" : "200",
"doc_count" : 1,
"_score2_sum" : {
"value" : 100.0
},
"_score1_sum" : {
"value" : 100.0
}
}
]
}
}
}
請注意,有兩個鍵的rank > 1000
,它們的_score1
和_score2
得分總和為400
,這是預期的結果。
讓我知道這是否有幫助!
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