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Spring數據jpa中與空點異常的多對多關系

[英]many to many relationship with nullpoint exception in spring data jpa

這是我的文件類

@Entity
@Table(name = "file")
public class File{

public File() {
 }
public File(String file_id,String file_path,Date start_time,Date end_time) {

         this.file_id=file_id;
         this.file_path=file_path;
         this.start_time=start_time;
         this.end_time=end_time;
         }
@Id
private String file_id;
private String file_path;
private Date start_time;//time
private Date end_time;//time
@JsonBackReference(value = "MainScheduleHasFile-File")
@OneToMany(mappedBy = "file",cascade = {CascadeType.ALL})
                private Set<MainScheduleHasFile> mainScheduleHasFiles = new HashSet<>();

    //getters and setters and other attributes 

這是我的 mainSchedule 類

@Entity
@Table(name = "main_schedule")
public class MainSchedule{

public MainSchedule() {

}
public MainSchedule(String scheduleId,double version) {
        this.scheduleId=scheduleId;
        this.version=version;

    }
@Id
private String scheduleId;
private double version;

@JsonBackReference(value = "MainScheduleHasFile-MainSchedule")
@OneToMany(mappedBy = "mainSchedule",cascade = { CascadeType.ALL  })
private Set<MainScheduleHasFile> mainScheduleHasFile;

//getters and setters and other attributes

我的 mainSchedulePlayFile 類

@Entity
@Table(name = "main_schedule_play_file")
public class MainSchedulePlayFile implements Serializable{

public MainSchedulePlayFile() {

}

public MainSchedulePlayFile(MainSchedule mainSchedule, File file) {
            this.mainSchedule=mainSchedule;
            this.file=file;
        }


@Id
@ManyToOne
@JoinColumn(name = "schedule_id")
private MainSchedule mainSchedule;

@Id
@ManyToOne
@JoinColumn(name = "file_id")
private  File file;
private Integer playPoint;

//getters and setters and other attributes 

數據插入邏輯

MainSchedulePlayFile mSchFile=new MainSchedulePlayFile();
Set<MainSchedulePlayFile> set=new HashSet<>();
MainSchedule m=mainScheduleRepo.findById(mid).get();
mSchFile.setMainSchedule(m);
mSchFile.setFile(fileRepo.findById(fid).get());
mSchFile.setPlayPoint(1);

set.add(mSchFile);
m.setMainSchedulePlayFile(set);
mainScheduleRepo.save(m);

這是錯誤。

20-03-19 Thu 00:39:53.532 DEBUG SQL select mainschedu0_.schedule_id as schedule2_4_0_, mainschedu0_.file_id as file_id3_4_0_, mainschedu0_.play_point as play_poi1_4_0_ from main_schedule_has_file mainschedu0_ where mainschedu0_.schedule_id=? and mainschedu0_.file_id=?
Hibernate: select mainschedu0_.schedule_id as schedule2_4_0_, mainschedu0_.file_id as file_id3_4_0_, mainschedu0_.play_point as play_poi1_4_0_ from main_schedule_has_file mainschedu0_ where mainschedu0_.schedule_id=? and mainschedu0_.file_id=?
20-03-19 Thu 00:39:53.533 TRACE BasicBinder binding parameter [1] as [VARCHAR] - [s001]
20-03-19 Thu 00:39:53.534 TRACE BasicBinder binding parameter [2] as [VARCHAR] - [f001]
20-03-19 Thu 00:39:53.598 DEBUG SQL insert into main_schedule_has_file (play_point, schedule_id, file_id) values (?, ?, ?)
 Hibernate: insert into main_schedule_has_file (play_point, schedule_id, file_id) values (?, ?, ?)
 20-03-19 Thu 00:39:53.604 TRACE BasicBinder binding parameter [1] as [INTEGER] - [1]
20-03-19 Thu 00:39:53.605 TRACE BasicBinder binding parameter [2] as [VARCHAR] - [null]
20-03-19 Thu 00:39:53.606 TRACE BasicBinder binding parameter [3] as [VARCHAR] - [null]
20-03-19 Thu 00:39:53.639 WARN  SqlExceptionHelper SQL Error: 1048, SQLState: 23000
20-03-19 Thu 00:39:53.639 ERROR SqlExceptionHelper Column 'schedule_id' cannot be null
20-03-19 Thu 00:39:53.670 ERROR [dispatcherServlet] Servlet.service() for servlet [dispatcherServlet] in context with path [] threw exception [Request processing failed; nested exception is org.springframework.dao.DataIntegrityViolationException: could not execute statement; SQL [n/a]; constraint [null]; nested exception is org.hibernate.exception.ConstraintViolationException: could not execute statement] with root cause
java.sql.SQLIntegrityConstraintViolationException: Column 'schedule_id' cannot be null

當我嘗試將數據添加到多對多關系時,會出現此錯誤。 如何解決這個問題? 我試圖在關系表中添加一個額外列的數據,但是如果有人可以解決這個錯誤,請幫助我!!!

我已經解決了。 數據插入邏輯應該是。

MainSchedulePlayFile mSchFile=new MainSchedulePlayFile(); MainSchedule
m=mainScheduleRepo.findById(mid).get(); 

mSchFile.setMainSchedule(m);
mSchFile.setFile(fileRepo.findById(fid).get());
mSchFile.setPlayPoint(1);

m.getMainSchedulePlayFile().add(mSchFile);

fileRepo.save mainScheduleRepo.save(m);

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