循環遍歷字符串列表並刪除特定列表項 (i) 之后的所有項，其中 i 可以是 a 或 b 或 c

Question

在列表中搜索並刪除包含在 Audi 或 Mazda 或 Suzuki 之后的所有其他內容。 請注意，列表中只能包含3個中的一個，但不能包含兩個或全部。 只有其中之一

第一個場景： if it's Audi,給出一個列表（列表項是隨機的）：

lst = ["Nissan","Chevrolet","Audi","Mercedes","BMW","Subaru","Mitsubishi"]

預期結果：

new_lst = ["Nissan","Chevrolet"]

場景2： If it's Suzuki 。

預期結果

lst = ["Nissan","Chevrolet","Mercedes","BMW","Subaru","Suzuki","Mitsubishi"]

new_lst = ["Nissan","Chevrolet","Mercedes","BMW","Subaru"]

等等等等

Answer 1

您可以使用itertools.takewhile來創建一個新列表並在適當的點“突破”

>>> from itertools import takewhile
>>> lst = ["Nissan","Chevrolet","Audi","Mercedes","BMW","Subaru","Mitsubishi"]
>>> list(takewhile(lambda x: x != "Audi", lst))
['Nissan', 'Chevrolet']

Answer 2

將列表切片與list.index一起list.index

前任：

lst = ["Nissan","Chevrolet","Audi","Mercedes","BMW","Subaru","Mitsubishi"]
print(lst[:lst.index("Audi")])

lst = ["Nissan","Chevrolet","Mercedes","BMW","Subaru","Suzuki","Mitsubishi"]
print(lst[:lst.index("Suzuki")])

輸出：

['Nissan', 'Chevrolet']
['Nissan', 'Chevrolet', 'Mercedes', 'BMW', 'Subaru']