[英]React how to ignore onClick for child element
我在父組件中有一個子組件。 我想在我點擊父級內部的任何地方時發出警報消息,除非點擊子級。
class TodoApp extends React.Component {
constructor(props) {
super(props)
this.state = {
}
}
render() {
return (
<div className="parent" onClick={() => alert('x')}>
<p>Alert clicks anywhere on this div</p>
<div className="children">
<button>Do not alert On this element click</button>
</div>
<p>Alert clicks anywhere on this div</p>
</div>
)
}
}
代碼示例在這里:
將 e.stopPropagation() 添加到子 onClick 屬性
class TodoApp extends React.Component {
constructor(props) {
super(props)
this.state = {
}
}
render() {
return (
<div className="parent" onClick={() => alert('x')}>
<p>Alert clicks anywhere on this div</p>
<div onClick={(e) => e.stopPropagation()} className="children">
<button>Do not alert On this element click</button>
</div>
<p>Alert clicks anywhere on this div</p>
</div>
)
}
}
您可以防止子元素中的事件傳播,即
<button onClick={((e) => e.stopPropagation())}>Do not alert On this element click</button>
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