如何在 SQL Java 中將列表值作為參數傳遞

Question

我有一個 sql 查詢（將值從一個表復制到同一數據庫中的另一個表），它采用多個值作為參數，值來自列表。

下面是我嘗試過的。雖然我沒有收到任何錯誤，但它不起作用。我想將值插入數據庫列表 EmployeeIDList= new ArrayList(Arrays.asList(123,823,456,890)); List SalaryList= new ArrayList(Arrays.asList(14437,14297,13846,13441));

con1=DriverManager.getConnection(URL1,DB_UserName,DB_Password);
log.info("Data base connection is established");        
for (int i=0,j=0;i<EmployeeIDList.size();i++,j++) {
    stmt = con1.prepareStatement("Insert INTO Employee(Name, Year, EmployeeID, Tax, Salary)                 
            Select Name, Year, EmployeeID, Tax, Salary 
             (Employee

                       when EmployeeID= ? then ?   // 1st ? = EmployeeID,2nd ? = Salary
                       when EmployeeID = ? then ?         
                       when EmployeeID = ? then ?
                       else ?  // ? = Salary
                       end ) as Employee
                "From Employee2 + 
                "Where EmployeeIDin (?)");

        stmt.setInt(1,SalaryList.get(j));
        stmt.setInt(2,EmployeeIDList.get(i));           
        System.out.println("first salry is " +SalaryList.get(j))    ;
        System.out.println("first Employeeid is " +EmployeeIDList.get(i))   ;
        rs = stmt.execute();

當我在 sql 中執行“select * from Employee”時，它不返回任何值。

注意：如果我在 sql 中執行上面的插入查詢，它工作正常。只有通過 java 我無法插入值。

Answer 1

請試試這些代碼 String query = " Insert INTO Employee(Name, Year, EmployeeID, Tax, Salary)" + " values (?, ?, ?, ?, ?)"; 然后應用選擇查詢

Answer 2

我已經解決了。setInt中的位置編號有誤。謝謝大家