[英]How can i get a url param for an updateview in django?
網址:
`path('my-domains/<str:domain_name>/dns-settings', login_required(DNSSettingsUpdateView.as_view()), name='dns_settings')`
我想讓 str:domain_name 在我的更新視圖中使用:
class DNSSettingsUpdateView(UpdateView):
model = Domain
form_class = NsRecordModelForm
template_name = "engine/dns_settings.html"
def get_object(self, queryset=None):
return Domain.objects.get(name=[would insert it here])
def get_success_url(self):
return reverse("my-domains")
我怎樣才能做到這一點? 有人可以幫忙嗎? 提前致謝
您可以通過self.kwargs
訪問 url 參數,它是一個將參數名稱映射到它們的值的字典,因此:
class DNSSettingsUpdateView(UpdateView):
model = Domain
form_class = NsRecordModelForm
template_name = "engine/dns_settings.html"
def get_object(self, queryset=None):
return Domain.objects.get(name=self.kwargs['domain_name'])
def get_success_url(self):
return reverse("my-domains")
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.