如何將基於類的視圖轉換為基於函數的視圖？ - Django

Question

我正在嘗試將所有基於類的視圖更改為基於函數的視圖，並且在轉換以下 class 時遇到困難：

class PostUpdateView(LoginRequiredMixin, UserPassesTestMixin, SuccessMessageMixin, UpdateView):
    model = Post
    fields = ['image', 'title', 'category', status', 'description']
    template_name = 'blog/post-form.html'
    success_message = 'Your post has been updated.'

    def form_valid(self, form):
        form.instance.author = self.request.user
        return super().form_valid(form)

    def test_func(self):
        post = self.get_object()
        if self.request.user == post.author:
            return True
        return False

    def get_context_data(self, **kwargs):
        context = super(PostUpdateView, self).get_context_data(**kwargs)
        context['title'] = 'Update post'
        context['submit'] = 'Update'
        return context

    def get_success_url(self):
        author = self.object.author 
        return reverse_lazy( 'profile', kwargs={'author': author.username})

function 和表單應該完全符合這個基於類的視圖的功能，所以如果有人可以幫助我，請告訴我。

Answer 1

您可以在UpdateView （以及CreateView ）中指定.form_class屬性 [Django-doc] 。 所以我們可以創建一個像這樣的表單：

# app/forms.py

from django import forms

class PostForm(forms.ModelForm):
    class Meta:
        model = Post
        fields = ['image', 'title', 'category', 'status', 'description']
        widgets = {
            'image': …
        }

在哪里替換…為您要用於image字段的小部件。

然后您可以插入該表單：

# app/views.py

from app.forms import PostForm

class PostUpdateView(LoginRequiredMixin, UserPassesTestMixin, SuccessMessageMixin, UpdateView):
    model = Post
    form_class = PostForm
    template_name = 'blog/post-form.html'
    success_message = 'Your post has been updated.'

    def form_valid(self, form):
        form.instance.author = self.request.user
        return super().form_valid(form)

    def test_func(self):
        post = self.get_object()
        if self.request.user == post.author:
            return True
        return False

    def get_context_data(self, **kwargs):
        context = super(PostUpdateView, self).get_context_data(**kwargs)
        context['title'] = 'Update post'
        context['submit'] = 'Update'
        return context

    def get_success_url(self):
        author = self.object.author 
        return reverse_lazy( 'profile', kwargs={'author': author.username})

在幕后，如果您不指定form_class ，Django 將簡單地使用 modelform_factory modelform_factory Django-doc]為您制作一個，因此通過使用另一個ModelForm ，我們不會改變使用表單的邏輯。