以超鏈接形式返回 PHP 表單數據
[英]Return PHP Form data as hyperlinks
問題描述
我正在嘗試從我的 php 表單中返回我的 output 數據作為要打開的超鏈接
我的代碼：
<?php
error_reporting(0);
$name = $_POST['name'];
$time = $_POST['time'];
$calls = $_POST['calls'];
$task1 = $_POST['task1'];
$task2 = $_POST['task2'];
$task3 = $_POST['task3'];
$task4 = $_POST['task4'];
$task5 = $_POST['task5'];
if ($_POST['clear'])
{
$name="";
$time="";
$calls="";
$task1="";
$task2="";
$task3="";
$task4="";
$task5="";
$message1="";
$message2="";
$message3="";
$message4="";
}
if ($_POST['send'])
{
$message1 = "Hello ,<br><br>Here's my $time update.";
$message2 = "<br>"."Task Numbers :"."<br><br>".$task1 ."<br>".$task2 ."<br>" .$task3 ."<br>" .$task4 ."<br>".$task5."<br>";
$message3 = "Total calls for the hour : <strong>$calls</strong>";
$message4 = "<br>". "<br>". "Kind Regards"."<br>". "Employee";
}
?>
<html>
<style>
body {
font-family:arial;
font-size:12;
}
</style>
<title>Productivity Generator</title>
<form action = "" method = "POST">
<body>
<table border = 3>
<tr>
<td> Time: </td>
<td> <input list="times" name ="time" value = "<?php echo $time;?>" size="20">
<datalist id="times">
<option value="5AM">
<option value="6AM">
<option value="7AM">
<option value="8AM">
<option value="9AM">
<option value="10AM">
<option value="11AM">
<option value="12PM">
<option value="1PM">
<option value="1:30PM">
<option value="2PM">
<option value="2:30PM">
</datalist>
</tr>
<td> Calls: </td>
<td> <input type ="number" name ="calls" autocomplete="off" value = "<?php echo $calls;?>" size="20">
</tr>
<tr>
<td> Task1: </td>
<td> <input type = text name ="task1" autocomplete="off" value = "<?php echo $task1;?>" size="20" >
</tr>
<td> Task2: </td>
<td> <input type = text name ="task2" autocomplete="off" value = "<?php echo $task2;?>" size="20" >
</tr>
<td> Task3: </td>
<td> <input type = text name ="task3" autocomplete="off" value = "<?php echo $task3;?>" size="20" >
</tr>
<td> Task4: </td>
<td> <input type = text name ="task4" autocomplete="off" value = "<?php echo $task4;?>" size="20" >
</tr>
<td> Task5: </td>
<td> <input type = text name ="task5" value = "<?php echo $task5;?>" size="20" >
</tr>
<tr>
<td colspan = 3>
<input type = "submit" name="send" value = "Ok" title="Click here to display values.">
<input type = "submit" name="clear" value = "Clear" title="Click here to clear text boxes.">
</td>
</tr>
</table>
</form>
<?php
echo "<br><br>";
echo "<font face='arial' size='2'>";
echo $message1;
echo "<br>";
echo $message2;
echo "<br>";
echo $message3;
echo "<br>";
echo $message4;
echo "</font>";
?>
</body>
</html>
用戶輸入的每個任務編號將 output 作為超鏈接，一旦您單擊超鏈接，它將打開一個新選項卡，例如： https://google.com/%user input%
非常感謝任何幫助，我無法弄清楚如何在 php 中實現這一點，請客氣，我是 php 的新手哈哈
1 個解決方案
解決方案1
0 已采納 2020-04-03 22:13:05
您必須使用錨標簽才能將 output 作為超鏈接。 此外，您必須使用目標屬性在新選項卡中打開該鏈接。
希望這對你有幫助！
$link = $_SERVER['REQUEST_URI']; //Base Uri
$message2 = "<br>"."Task Numbers :"."<br><br>"."<a target=_blank href=".$link.'/'.$task1.">Task1</a>"."<br>"."<a target=_blank href=".$link.'/'.$task2.">Task2</a>"."<br>"."<a target=_blank href=".$link.'/'.$task3.">Task3</a>"."<br>" ."<a target=_blank href=".$link.'/'.$task4.">Task4</a>"."<br>"."<a target=_blank href=".$link.'/'.$task5.">Task5</a>"."<br>";
PHP MYSQL超鏈接和表單字段
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