添加數組的連續元素

Question

嘗試將數組的兩個元素相加，即

• [2,4,6,8,10,12] 應該返回一個新數組 [6, 14, 22] (2+4, 6+8, 10+12)
• [4,2,7,15,35,23] 應該返回一個新數組 [6,22,58] - (4+2, 7+15, 35+23)

新的、沮喪的並且無法正確地制定一個 for 循環來達到預期的結果。

到目前為止我嘗試過的錯誤解決方案：

 var newArray = [];

  for (let i = 0; i<numbers.length - 1; i +=2) {
    newArray = numbers.push(numbers[i] + numbers[i] + 1);
    console.log(newArray);
  }

Answer 1

快速簡單，假設輸入總是一個偶數長度的數組

const data = [4,2,7,15,35,23]
const length = data.length
const res = []
for(let i = 0; i < length; i+=2){
  var num1 = data[i]
  var num2 = data[i + 1]
  res.push(num1 + num2)
}
console.log(res)

Answer 2

你很親密：

let newArray = [];

const numbers = [2,4,6,8,10,12];

for (let i = 0; i < numbers.length - 1; i += 2) {
  newArray.push(numbers[i] + numbers[i + 1]);
}

console.log(newArray);