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如何在不使用 InetAddress 類或避免 10 分鍾緩存時間的情況下獲取 DNS 解析時間?

[英]How to get the DNS resolution time without using the class InetAddress or avoiding the 10 min cached time?

我一直在嘗試使用下一個代碼獲取 DNS 解析時間:

val url = URL(dataExperienceTestResult.pingUrl)
val host: String = url.host

val currentTime: Long = SystemClock.elapsedRealtime()
val address: InetAddress = InetAddress.getByName(host)
val dnsTime: Long = SystemClock.elapsedRealtime() - currentTime

這按預期工作,為我提供了合理的解析時間(使用數據為 100 毫秒),但是,這只是第一次嘗試的情況,因為下一個解析時間太短(使用數據為 0-2 毫秒)。 閱讀文檔后,我可以找到原因是因為如果成功,它會緩存 10 分鍾。

我嘗試使用反射調用類InerAddress的隱藏方法clearDnsCache()具有稍高的結果(使用數據為 2-4 毫秒),因此緩存似乎沒有被完全清除:

//The position 0 method of the list is clearDnsCache()
val method = Class.forName(InetAddress::class.java.name).methods[0]
method.invoke(Class.forName(InetAddress::class.java.name))

我還嘗試了我在其他 StackOverflow 問題中讀到的解決方案,其中包括使用 JVM 機器的安全屬性。 它沒有用,我想這是因為它需要 root。

Security.setProperty("networkaddress.cache.ttl", "0")

我目前正在處理的最后一個選項包括使用 DnsResolver 類發送查詢,但我得到了很高的結果(300 毫秒 - 第一個為真,接下來 200 毫秒嘗試使用數據)。

    private static final char[] HEX_CHARS = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'A', 'B', 'C', 'D', 'E', 'F'};
    long currentTime;

    @RequiresApi(api = Build.VERSION_CODES.Q)
    public void method(Context context){
        URL url;
        Executor executor = new Handler(Looper.getMainLooper())::post;

        try {
            url = new URL("https://ee-uk.metricelltestcloud.com/SpeedTest/latency.txt");
//
            String host = url.getHost();
            final String msg = "RawQuery " + host;

            if (android.os.Build.VERSION.SDK_INT >= android.os.Build.VERSION_CODES.M) {
                ConnectivityManager connectivityManager = (ConnectivityManager) context.getSystemService(CONNECTIVITY_SERVICE);
                if (connectivityManager != null) {

                    Network[] networks = connectivityManager.getAllNetworks();
                    currentTime = SystemClock.elapsedRealtime();
                    for (Network network : networks){
                        final VerifyCancelCallback callback = new VerifyCancelCallback(msg);

                        if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.Q) {
                            DnsResolver resolver = DnsResolver.getInstance();
                            resolver.rawQuery(network, host, CLASS_IN, TYPE_AAAA, FLAG_NO_CACHE_LOOKUP, executor, null, callback);
                        }
                    }
                }
            }


        } catch (MalformedURLException e) {
            e.printStackTrace();
        }
    }
    private static String byteArrayToHexString(byte[] bytes) {
        char[] hexChars = new char[bytes.length * 2];
        for (int i = 0; i < bytes.length; ++i) {
            int b = bytes[i] & 0xFF;
            hexChars[i * 2] = HEX_CHARS[b >>> 4];
            hexChars[i * 2 + 1] = HEX_CHARS[b & 0x0F];
        }
        return new String(hexChars);
    }

    @RequiresApi(api = Build.VERSION_CODES.Q)
    class VerifyCancelCallback implements DnsResolver.Callback<byte[]> {
        private String mMsg;
        VerifyCancelCallback(@NonNull String msg) {
            this.mMsg = msg;
//            this(msg, null);
        }
        @Override
        public void onAnswer(@NonNull byte[] answer, int rcode) {
            long dnsTime = SystemClock.elapsedRealtime() - currentTime;
            Log.v("Kanto_Resolver", "Answer " + dnsTime + " ms");
            Log.v("Kanto_resolver", answer.toString());
            Log.d("Kanto_resolver", "Reported rcode: " + rcode);
            Log.d("Kanto_resolver", "Reported blob: " + byteArrayToHexString(answer));
        }
        @Override
        public void onError(@NonNull DnsResolver.DnsException error) {
            Log.v("Kanto_Resolver", "Error");
        }
    }

問題:您是否知道一種無需使用“InetAddress.getByName()”即可解析 DNS 的方法或一種完全清除 DNS 緩存的方法?

我需要:每次檢查時獲取真實的(未緩存的)DNS 解析時間,而不考慮上次檢查的時間。

我知道 StackOverflow 中已經有一些關於同一主題的問題,但它們中的大多數都太舊了,根本無法解決我的問題。

由於這篇文章中的 VisualBasic 代碼,我可以找到另一種方法來獲取 DNS 解析時間和已解析的 IP 地址,從而避免緩存

該解決方案包括通過套接字向 DNS IP 解析器發送帶有特定查詢的 DatagramPacket,然后我們等待答案,即解析時間,我們分析答案以找到已解析的 IP。

看代碼:

在一個新線程中,我們創建數據包,發送它,接收它並解碼它:

public void getDnsStuff() {
    backgroundHandler.post(new Runnable() {
        @Override
        public void run() {

            byte [] lololo;
            try {
                DatagramPacket sendPacket;
                String string = "linkedin.com";
                lololo = giveMeX3(urlToUse);
                sendPacket = new DatagramPacket(lololo, lololo.length, InetAddress.getByName("8.8.8.8"), 53);
                Log.e("kanto_extra", "host: " + string + ", DNS: GoogleDNS");

                socket = new DatagramSocket();
                socket.send(sendPacket);

                byte[] buf = new byte[512];
                DatagramPacket receivePacket = new DatagramPacket(buf, buf.length);

                Long currentTime = SystemClock.elapsedRealtime();
                socket.setSoTimeout(1000);
                socket.receive(receivePacket);
                Long now = SystemClock.elapsedRealtime() - currentTime;
                Log.v("Kanto_time", now.toString());

                int[] bufUnsigned = new int[receivePacket.getLength()];
                for (int x = 0; x < receivePacket.getLength(); x++){
                    bufUnsigned[x] = (int) receivePacket.getData()[x] & 0xFF;
                }
                Log.v("Kanto_unsigned", bufUnsigned.toString());

                letsDoSomethingWIthThoseBytes(bufUnsigned, receivePacket.getData(), lololo, now);

            } catch (IOException e) {
                e.printStackTrace();
            }

            socket.close();
            socket.disconnect();

            }

    });
}

對要發送的查詢進行編碼的方法(giveMeX3):

private byte[] giveMeX3(String host){
    String TransactionID1="Q1";
    String TypeString="\u0001"+"\u0000"+"\u0000"+"\u0001"+"\u0000"+"\u0000"+"\u0000"+"\u0000"+"\u0000"+"\u0000";
    String TrailerString="\u0000"+"\u0000"+"\u0001"+"\u0000"+"\u0001";
    String URLNameStart = host.substring(0, host.indexOf("."));
    String DomainName = host.substring(host.indexOf(".") + 1);
    String QueryString = TransactionID1 + TypeString + (char)URLNameStart.length() + URLNameStart + (char)DomainName.length() + DomainName + TrailerString;

    byte[] buffer = new byte[0];
    if (android.os.Build.VERSION.SDK_INT >= android.os.Build.VERSION_CODES.KITKAT) {
        buffer = QueryString.getBytes(StandardCharsets.US_ASCII);
    }
    return buffer;
}

解碼答案的字節數組的方法(letsDoSomethingWIthThoseBytes):

public void letsDoSomethingWIthThoseBytes(int[] bytesList, byte[] bytesListTrue, byte[] sentBytes, Long time){
    int index = 0;
    if (bytesList[0] == sentBytes[0] && (bytesList[1] == 0x31) || (bytesList[1] == 0x32)) {
        if (bytesList[2] == 0x81 && bytesList[3] == 0x80) {

            // Decode the answers
            // Find the URL that was returned
            int TransactionDNS = bytesList[1];
            String ReceiveString = "";// = Encoding.ASCII.GetString(Receivebytes);
            if (android.os.Build.VERSION.SDK_INT >= android.os.Build.VERSION_CODES.KITKAT) {
                ReceiveString = new String(bytesListTrue, StandardCharsets.US_ASCII);
            }
            index=12;
            int URLNameStartLength = bytesListTrue[index];
            index++;
            String URLNameStart = ReceiveString.substring(index,URLNameStartLength + index);
            index=index+URLNameStartLength;
            int DomainNameLength = bytesListTrue[index];
            index++;
            String DomainName = ReceiveString.substring(index,DomainNameLength + index);
            index=index+DomainNameLength;
            index=index+8;

            // Get the record type
            int ResponseType = bytesListTrue[index];
            index=index+9;

            int listLenght = bytesList.length;
            String IPResponse = String.valueOf(bytesList[index])+"."
                    + String.valueOf(bytesList[index + 1])+"."
                    + String.valueOf(bytesList[index + 2])+"."
                    + String.valueOf(bytesList[index + 3]);

            this.resultString = URLNameStart + "." + DomainName + " - " + IPResponse + " - " + time.toString();
            Log.v("Kanto DNS answer", URLNameStart + "." + DomainName + " - " + IPResponse + " - " + time.toString());
        }
    }

}

附加信息:

  • 據我所知,可以根據您需要從 DNS 服務器獲取什么來修改要發送到服務器的查詢。 您可以在此處了解有關 DNS 協議的更多信息

  • 在這個例子中,我正在與 Google DNS (8.8.8.8 / 8.8.4.4) 通信,但我測試了很多,並且所有這些都使用端口 53,所以它們應該可以工作。 檢查一些DNS服務器:

    ("Google", "8.8.8.8", "8.8.4.4", "https://developers.google.com/speed/public-dns");
    ("Quad9", "9.9.9.9", "149.112.112.112", "https://www.quad9.net/");
    ("Level 3", "209.244.0.3", "209.244.0.4", "https://www.centurylink.com/business.html?rid=lvltmigration");
    ("Yandex", "77.88.8.8", "77.88.8.1", "https://dns.yandex.com/");
    ("DNSWatch", "84.200.69.80", "84.200.70.40", "https://dns.watch/index");
    ("Verisign", "64.6.64.6", "64.6.65.6", "https://www.verisign.com/en_GB/security-services/public-dns/index.xhtml");
    ("OpenDNS", "208.67.222.222", "208.67.220.220", "https://www.opendns.com/");
    ("FreeDNS", "37.235.1.174", "37.235.1.177", "https://freedns.zone");
    ("Cloudflare", "1.1.1.1", "1.0.0.1", "https://1.1.1.1");
    ("AdGuard", "176.103.130.130", "176.103.130.131", "https://adguard.com/en/adguard-dns/overview.html#instruction");
    ("French Data Network", "80.67.169.12", "80.67.169.40", "https://www.fdn.fr/actions/dns/");
    ("Comodo", "8.26.56.26", "8.20.247.20", "https://www.comodo.com/secure-dns/");
    ("Alternate DNS", "23.253.163.53", "198.101.242.72", "https://alternate-dns.com/");
    ("Freenom World", "80.80.80.80", "80.80.81.81", "https://www.freenom.com");
    ("Keweon", "176.9.62.58", "176.9.62.62", "https://forum.xda-developers.com/android/software-hacking/keweon-privacy-online-security-t3681139");
    ("Quad101", "101.101.101.101", "101.102.103.104", "https://101.101.101.101/index_en.html");
    ("SafeDNS", "195.46.39.39", "195.46.39.40", "https://www.safedns.com/en/");
    ("UncensoredDNS", "91.239.100.100", "89.233.43.71", "https://blog.uncensoreddns.org/");
  • 我從大多數 DNS 服務器收到的大多數答案都包含在字節數組末尾的已解析 IP 地址,特別是最后 4 個字節,但是,並非所有這些都是這種情況。

希望此解決方案對某些人有所幫助。

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