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[英]Laravel/Lumen Model query with:: and where: How to do this right?
[英]Multiple Where Has Query in Lumen / Laravel Problem
我只是想在這種特定情況下尋求幫助。 因此,在我的應用程序中,我們希望進行全局搜索 function 放置 1 個字符串,然后我們必須使用 laravel Z4B4D28FC143CA344E48631AFF6183 在數據庫中的多種情況下搜索該字符串有withcount(我稍后會展示)。 有人可以幫我解決這個問題嗎? 將不勝感激
這是代碼
$result = [];
$sort_order = "DESC";
$post_param = $request->json()->all();
$filters = $post_param['filters'];
if($post_param['sortOrder'] > 0)
{
$sort_order = "ASC";
}
$financing_applications = $this->financing_application->model();
$data = $financing_applications::with('financing_application_data.business_type','financing_product_approval.financing_product')->withCount('financing_application_attachments as attachment');
foreach($filters as $key => $filter){
$value = $filter['value'];
if($value != ""){
switch($key){
case "start_date_range":
$data = $data->where('submission_date','>=',$value);
break;
case "end_date_range":
$data = $data->where('submission_date','<=',$value);
break;
case "status":
$data = $data->where($key,"LIKE","%$value%");
break;
case "attachment_count":
$data = $data->having('attachment_count','=',$value);
break;
case "company_name":
case "telephone":
case "city":
if($key == "telephone"){
$key = "personal_phone_no";
}
if($key == "city"){
$key = "company_city";
}
$data = $data->whereHas('financing_application_data',function($query) use ($key,$value) {
$query->where($key,"LIKE","%$value%");
});
break;
case "business_type":
$data->whereHas('financing_application_data.business_type',function($query) use ($key,$value){
$query->where('business_type_parent','LIKE',"%$value%");
});
break;
case "loan_type":
case "loan_partner":
$data->whereHas('financing_product_approval.financing_product',function($query) use ($key,$value){
$query->where($key,"LIKE","%$value%");
});
break;
case "global": //This is the problem
$data = $data->whereHas('financing_application_data.business_type',function($query) use ($key,$value){
$query->whereRaw("business_type_parent LIKE ? ",["%$value%"]);
});
$data = $data->whereHas('financing_product_approval.financing_product',function($query) use ($key,$value){
$query->whereRaw("loan_type LIKE ? OR loan_partner LIKE ?",["%$value%","%$value%"]);
});
break;
}
}
}
$total_records = $data->count();
$result = $data->orderBy($post_param['sortField'],$sort_order)->skip($post_param['first'])->take($post_param['rows'])->get();
return [
"financing_applications" => $result,
"total_records" => $total_records,
"message" => "",
"status" => 200,
];
因此,在這種情況下,我的預期結果是能夠使用所有案例並將其組合到 switch 語句中的“全局”案例中。
有沒有人有同樣的問題並有解決方案? 上述全局不起作用,因為 where 和 whereHas 預期為 AND 而不是 OR... 我一直在尋找解決方案,但它太復雜了我不知道這個問題的確切關鍵字
這是您需要的一些信息
"laravel/lumen-framework": "5.3.*"
更新:如果你們中的一些人誤解了我的問題,我很抱歉,所以問題只出在“全局”的情況下,現在另一種情況在於“whereHas”語法來過濾關系。 如果全局應該能夠結合“Where”和“WhereHas”,我已經這樣做了,但是因為沒有“orWhereHas”(只要我知道),所以它將返回空,因為它識別為“AND”語句
這里我給你 json 有效載荷:
{
"filters": {
"global": {
"matchMode": "undefined",
"type": "string",
"value": "Man"
},
"start_date_range": {
"matchMode": "undefined",
"type": "date",
"value": ""
},
"end_date_range": {
"matchMode": "undefined",
"type": "date",
"value": ""
},
"company_name": {
"matchMode": "undefined",
"type": "string",
"value": ""
},
"business_type": {
"matchMode": "undefined",
"type": "string",
"value": ""
},
"telephone": {
"matchMode": "undefined",
"type": "string",
"value": ""
},
"city": {
"matchMode": "undefined",
"type": "string",
"value": ""
},
"attachment_count": {
"matchMode": "undefined",
"type": "string",
"value": ""
},
"loan_type": {
"matchMode": "undefined",
"type": "string",
"value": ""
},
"loan_partner": {
"matchMode": "undefined",
"type": "string",
"value": ""
},
"status": {
"matchMode": "undefined",
"type": "string",
"value": ""
}
},
"first": 0,
"rows": 8,
"sortOrder": -1,
"sortField": "submission_date"
}
所以目標是讓 filter['global']['value'] 返回一些東西,這就是問題所在,希望它能澄清一些理解問題
我找到了解決這個問題的方法,我必須用 has 替換 whereHas 語法,它可以具有我在這種情況下需要的 OR 邏輯。
謝謝
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