[英]Can't figure how to get data from MySql Query
我之前問了一個關於如何進行此查詢的問題,並得到了很好的回應。 不幸的是,它比我通常運行的查詢要高級一些,所以我無法弄清楚如何檢索結果並將它們顯示在我的 web 頁面上。 這是原始問題原始問題的鏈接
<?php
// Associative array
$result = $db->query("SELECT Name,
COALESCE(AVG(CASE WHEN mth = 1 THEN PTS END), 0) AS Jan,
COALESCE(AVG(CASE WHEN mth = 2 THEN PTS END), 0) AS Feb,
COALESCE(AVG(CASE WHEN mth = 3 THEN PTS END), 0) AS Mar,
COALESCE(AVG(CASE WHEN mth = 4 THEN PTS END), 0) AS Apr,
COALESCE(AVG(CASE WHEN mth = 5 THEN PTS END), 0) AS May,
COALESCE(AVG(CASE WHEN mth = 6 THEN PTS END), 0) AS Jun,
COALESCE(AVG(CASE WHEN mth = 7 THEN PTS END), 0) AS Jul,
COALESCE(AVG(CASE WHEN mth = 8 THEN PTS END), 0) AS Aug,
COALESCE(AVG(CASE WHEN mth = 9 THEN PTS END), 0) AS Sep,
COALESCE(AVG(CASE WHEN mth = 10 THEN PTS END), 0) AS Oct,
COALESCE(AVG(CASE WHEN mth = 11 THEN PTS END), 0) AS Nov,
COALESCE(AVG(CASE WHEN mth = 12 THEN PTS END), 0) AS Dec,
AVG(PTS) AS AVG
FROM (
SELECT Name, `Points Pass` AS PTS, MONTH(STR_TO_DATE(`OS Date`, '%a %b %e %H:%i:%s %Y')) AS mth
FROM data
) d
GROUP BY Name");
while($row = mysqli_fetch_array($result)) {
?>
<tr>
<td><?php echo $row['Name']; ?></td>
<td class = "gScore-<?php echo $row['Jan']; ?>"><?php echo $row['Jan']; ?></td>
<td class = "gScore-<?php echo $row['Feb']; ?>"><?php echo $row['Feb']; ?></td>
<td class = "gScore-<?php echo $row['Mar']; ?>"><?php echo $row['Mar']; ?></td>
<td class = "gScore-<?php echo $row['Apr']; ?>"><?php echo $row['Apr']; ?></td>
<td class = "gScore-<?php echo $row['May']; ?>"><?php echo $row['May']; ?></td>
<td class = "gScore-<?php echo $row['Jun']; ?>"><?php echo $row['Jun']; ?></td>
<td class = "gScore-<?php echo $row['Jul']; ?>"><?php echo $row['Jul']; ?></td>
<td class = "gScore-<?php echo $row['Aug']; ?>"><?php echo $row['Aug']; ?></td>
<td class = "gScore-<?php echo $row['Sep']; ?>"><?php echo $row['Sep']; ?></td>
<td class = "gScore-<?php echo $row['Oct']; ?>"><?php echo $row['Oct']; ?></td>
<td class = "gScore-<?php echo $row['Nov']; ?>"><?php echo $row['Nov']; ?></td>
<td class = "gScore-<?php echo $row['Dec']; ?>"><?php echo $row['Dec']; ?></td>
<td><?php echo $row['AVG']; ?></td>
</tr>
<?php
}
if (!$result) { echo $db->error; }
你有幾個問題:
$row
的索引需要用引號括起來,例如$row['name']
否則你會得到很多“未定義的常量”警告;$row['Jan']
是檢索每月數據的正確方法,您需要為其他每個月復制它;$row['AVG']
替換$avgGrade
<td class = "gScore-<?php echo $row[Jan]; ?>"></td>
你真的想要嗎
<td class = "gScore"><?php echo $row[Jan]; ?></td>
-- repeat for May to November
行,即 $result = $db->query("SELECT name,
COALESCE(AVG(CASE WHEN mth = 1 THEN PTS END), 0) AS Jan,
COALESCE(AVG(CASE WHEN mth = 2 THEN PTS END), 0) AS Feb,
COALESCE(AVG(CASE WHEN mth = 3 THEN PTS END), 0) AS Mar,
COALESCE(AVG(CASE WHEN mth = 4 THEN PTS END), 0) AS Apr,
COALESCE(AVG(CASE WHEN mth = 5 THEN PTS END), 0) AS May,
COALESCE(AVG(CASE WHEN mth = 6 THEN PTS END), 0) AS Jun,
COALESCE(AVG(CASE WHEN mth = 7 THEN PTS END), 0) AS Jul,
COALESCE(AVG(CASE WHEN mth = 8 THEN PTS END), 0) AS Aug,
COALESCE(AVG(CASE WHEN mth = 9 THEN PTS END), 0) AS Sep,
COALESCE(AVG(CASE WHEN mth = 10 THEN PTS END), 0) AS Oct,
COALESCE(AVG(CASE WHEN mth = 11 THEN PTS END), 0) AS Nov,
COALESCE(AVG(CASE WHEN mth = 12 THEN PTS END), 0) AS `Dec`,
AVG(PTS) AS AVG
FROM (
SELECT name, PTS AS PTS, MONTH(STR_TO_DATE(DATE, '%a %b %e %H:%i:%s %Y')) AS mth
FROM data
) d
GROUP BY name");
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