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[英]Python compare two different CSV Files which values are not in the same rows
[英]Compare two json files with same name but different values in two files
我有兩個 json 文件,內容如下:
文件1:
{
"name": "SES_ENABLED",
"value": "true"
},
{
"name":"SES_ADDRESS",
"value":"email-xxxxxx.aws.com"
},
{
"name":"SES_FROM_EMAIL",
"value":"abc@gmail.com"
},
{
"name":"SES_TO_EMAIL",
"value":"123@gmail.com"
}
文件 2:
{
"name": "SES_ENABLED",
"value": "false"
},
{
"name":"SES_FROM_EMAIL",
"value":"xyz@gmail.com"
},
{
"name":"SES_ADDRESS",
"value":"emails-xyzyzyz.aws.com"
}
在上述兩個文件中,名稱變量將相同但值不同且順序不同,並且文件 1 中還有一個額外的字段
IE
{
"name": "SES_TO_EMAIL"
"value": "123@gmail.com"
}
從file1我如何比較file2中常見的“名稱”變量,以及如果file2中缺少任何字段而不是file1,我怎么能得到它。
例如:
在將file1與file2進行比較后,我需要得到output,如"name": "SES_TO_EMAIL"
。
任何解決方案都會非常有用。
提前致謝:)
假設每個文件都包含一個 stream 對象,一個簡單的jq程序就可以解決問題。
reduce inputs.name as $name ({}; .[input_filename] += [$name])
| (keys_unsorted | combinations(2)) as $pair
| (.[$pair[0]] - .[$pair[1]])[]
| "name: \(.) is not present in \($pair[1])"
調用:
jq -rnf prog.jq file1 file2 file3 ...
def compare(files):
# store all name into list of list
names = [[prop['name'] for prop in file] for file in files]
for i, name in enumerate(names):
# create a temporary list
temp_name = names.copy()
# remove current name in list
temp_name.pop(i)
for n in name:
for j, temp in enumerate(temp_name):
if not (n in temp): # if name in not present in the other file, print it
print('name: {} is not present in file {}'.format(n, (j+1 if j < i else j + 2)))
這是我的幼稚方式,我們需要將所有名稱存儲在list
並將每個名稱與該列表進行比較。 簡單地使用它
import json
# open the first file
with open('file1.json', 'r') as file:
file1 = json.load(file)
# open the second file
with open('file2.json', 'r') as file:
file2 = json.load(file)
# then compare them
compare([file1, file2])
output 將是這樣的
name: SES_TO_EMAIL is not present in file 2
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