Laravel 7.0 MySQL SQLSTATE[HY000]：一般錯誤：1824 無法打開引用的表

Question

系統信息：

• 操作系統：Ubuntu 19.10
• Laravel 版本：7.0
• PHP 版本：7.3.11-0ubuntu0.19.10.4
• MySQL 版本：mysql Ver 8.0.19-0ubuntu0.19.10.3 for Linux on x86_64（Ubuntu）

我正在構建一個小型 Laravel 應用程序，並且遇到了 MySQL 和關系的問題。 當我嘗試運行我的遷移時，這是我得到的錯誤：

SQLSTATE[HY000]: General error: 1824 Failed to open the referenced table 'customers_table' (SQL: alter table `customer_contacts` add constraint `customer_contacts_customer_id_foreign` foreign key (`customer_id`) references `customers_table` (`id`))

這是有問題的兩個遷移文件。

customer表和遷移：

<?php

use Illuminate\Database\Migrations\Migration;
use Illuminate\Database\Schema\Blueprint;
use Illuminate\Support\Facades\Schema;

class CreateCustomersTable extends Migration
{
    /**
     * Run the migrations.
     *
     * @return void
     */
    public function up()
    {
        Schema::create('customers', function (Blueprint $table) {
            $table->id();

            $table->string('company_name', 50);
            $table->string('phone_number', 20)->nullable();
            $table->string('fax_number', 20)->nullable();
            $table->string('address_line_1', 75)->nullable();
            $table->string('address_line_2', 75)->nullable();
            $table->string('city', 75)->nullable();
            $table->string('state', 30)->nullable();
            $table->string('zip', 11)->nullable();
            $table->string('industry', 100)->nullable();
            $table->text('notes')->nullable();

            $table->timestamps();
        });
    }

    /**
     * Reverse the migrations.
     *
     * @return void
     */
    public function down()
    {
        Schema::dropIfExists('customers');
    }
}

以及customer_contacts表和遷移：

<?php

use Illuminate\Database\Migrations\Migration;
use Illuminate\Database\Schema\Blueprint;
use Illuminate\Support\Facades\Schema;

class CreateCustomerContactsTable extends Migration
{
    /**
     * Run the migrations.
     *
     * @return void
     */
    public function up()
    {
        Schema::create('customer_contacts', function (Blueprint $table) {
            $table->id();
            $table->foreignId('customer_id')->constrained('customers_table');
            $table->string('name', 50);
            $table->string('title', 50);
            $table->string('project', 50);
            $table->string('email', 50);
            $table->string('mobile_phone', 20);
            $table->string('work_phone', 20);
            $table->timestamps();
        });
    }

    /**
     * Reverse the migrations.
     *
     * @return void
     */
    public function down()
    {
        Schema::dropIfExists('customer_contacts');
    }
}

這是我的database.php中的相關部分。php 文件：

...

'mysql' => [
            'driver' => 'mysql',
            'url' => env('DATABASE_URL'),
            'host' => env('DB_HOST', '127.0.0.1'),
            'port' => env('DB_PORT', '3306'),
            'database' => env('DB_DATABASE', 'forge'),
            'username' => env('DB_USERNAME', 'forge'),
            'password' => env('DB_PASSWORD', ''),
            'unix_socket' => env('DB_SOCKET', ''),
            'charset' => 'utf8mb4',
            'collation' => 'utf8mb4_unicode_ci',
            'prefix' => '',
            'prefix_indexes' => true,
            'strict' => true,
            'engine' => 'InnoDB',
            'options' => extension_loaded('pdo_mysql') ? array_filter([
                PDO::MYSQL_ATTR_SSL_CA => env('MYSQL_ATTR_SSL_CA'),
            ]) : [],
        ],

...

我嘗試將我的數據庫更改為 SQLite 以查看是否出現相同的錯誤，但我沒有，只有 MySQL 會創建此錯誤。

Answer 1

利用

$table->foreignId('customer_id')->constrained('customers')

代替

$table->foreignId('customer_id')->constrained('customers_table');

Answer 2

答案發布在這里： https://stackoverflow.com/a/61393131/7018549 。

利用

$table->foreignId('customer_id')->constrained('customers')

代替

$table->foreignId('customer_id')->constrained('customers_table');