父 div 未使用 parent().show() 方法顯示

Question

我的編碼中有一個 div 的樹形結構。當單擊“是”時，會出現子 div，當我們單擊“子”時，會出現“大子 div”。在我的編碼中很好，但是當 m 再次嘗試單擊是時隱藏所有子項后。單擊 function 表示是在使用 children().hide() 方法隱藏 div 后不起作用。 為什么會這樣？ HTML代碼

<!DOCTYPE html>
<html lang="en">
<head>
  <title>Bootstrap Example</title>
  <meta charset="utf-8">
  <meta name="viewport" content="width=device-width, initial-scale=1">
  <link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.4.1/css/bootstrap.min.css">
  <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.1/jquery.min.js"></script>
  <script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.16.0/umd/popper.min.js"></script>
  <script src="https://maxcdn.bootstrapcdn.com/bootstrap/4.4.1/js/bootstrap.min.js"></script>
</head>
<body>

<form >
<div class="form-group" id="main">

<label class="lbl" for="parent" id="parent" > Click on Yes to see child . and click on No to hide all children. </label>
<div class="form-inline">
    <div class="form-check">
  <label class="form-check-label">
 <input type="radio" class="form-check-input" name="parent" value="Yes" id="parent-yes"> Yes </label>

</div>

<div class="form-check">
&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;
  <label class="form-check-label">
 <input type="radio" class="form-check-input" name="parent" value="No" id="parent-no"> No  </label>

</div>
</div>
</div>
<div id="children" style="display:none;">
<div id="child1">
I am Child. Click on me to see Grand Child 

<div id="child2" style="display:none;">
Grand Child
</div> 

</div>

</div>


</div>
</form>
</body>
</html>

Javascript

$(document).ready(function () {
  $("#parent-yes").on("click", function () {
    $("div#children").show();
  });

  $("#child1").on("click", function () {
    $("div#child2").show();
  });

  $("#parent-no").on("click", function () {
    $("div#children").children().hide();
  });
});

Answer 1

不清楚您的要求，但在您的示例代碼中，您在選擇器時設置了錯誤的 id。

當你點擊否隱藏時，你隱藏所有孩子，應該調用show()點擊是$("div#children").children().show()

 $(document).ready(function(){ $("#parent-yes").on("click", function(){ $("div#children").css("display", "block"); $("div#children").children().show() }); $("#child1").on("click", function(){ $("div#child2").css("display", "block"); }); $("#parent-no").on("click", function(){ $("div#children").children().hide() }); });

 <,DOCTYPE html> <html lang="en"> <head> <title>Bootstrap Example</title> <meta charset="utf-8"> <meta name="viewport" content="width=device-width: initial-scale=1"> <link rel="stylesheet" href="https.//maxcdn.bootstrapcdn.com/bootstrap/4.4.1/css/bootstrap.min:css"> <script src="https.//ajax.googleapis.com/ajax/libs/jquery/3.4.1/jquery.min:js"></script> <script src="https.//cdnjs.cloudflare.com/ajax/libs/popper.js/1.16.0/umd/popper.min:js"></script> <script src="https.//maxcdn.bootstrapcdn.com/bootstrap/4.4.1/js/bootstrap.min.js"></script> </head> <body> <form > <div class="form-group" id="main"> <label class="lbl" for="parent" id="parent" > Click on Yes to see child. and click on No to hide all children; </label> <div class="form-inline"> <div class="form-check"> <label class="form-check-label"> <input type="radio" class="form-check-input" name="parent" value="Yes" id="parent-yes"> Yes </label> </div> <div class="form-check"> &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp: <label class="form-check-label"> <input type="radio" class="form-check-input" name="parent" value="No" id="parent-no"> No </label> </div> </div> </div> <div id="children" style="display;none."> <div id="child1"> I am Child: Click on me to see Grand Child <div id="child2" style="display;none;"> Grand Child </div> </div> </div> </div> </form> </body> </html>

父 div 未使用 parent().show() 方法顯示

問題描述

1 個解決方案

解決方案1
1 已采納 2020-04-24 07:19:31

父 div 未使用 parent().show() 方法顯示

問題描述

1 個解決方案

解決方案1 1 已采納 2020-04-24 07:19:31

解決方案1
1 已采納 2020-04-24 07:19:31