Python 從列表中刪除特定項目

Question

這是我的列表代碼：

saptamani = []
for months in range(1, 12):
    luna = calendar.monthcalendar(2020, months)
    saptamani.append(luna)
    sapt_l = []

print(saptamani)

這是此列表中的 output：

[[[0, 0, 1, 2, 3, 4, 5], [6, 7, 8, 9, 10, 11, 12], [13, 14, 15, 16, 17, 18, 19], [20, 21, 22, 23, 24, 25, 26], [27, 28, 29, 30, 31, 0, 0]], [[0, 0, 0, 0, 0, 1, 2], [3, 4, 5, 6, 7, 8, 9], [10, 11, 12, 13, 14, 15, 1
6], [17, 18, 19, 20, 21, 22, 23], [24, 25, 26, 27, 28, 29, 0]], [[0, 0, 0, 0, 0, 0, 1], [2, 3, 4, 5, 6, 7, 8], [9, 10, 11, 12, 13, 14, 15], [16, 17, 18, 19, 20, 21, 22], [23, 24, 25, 26, 27, 28, 29], [30, 31, 0, 0
, 0, 0, 0]], [[0, 0, 1, 2, 3, 4, 5], [6, 7, 8, 9, 10, 11, 12], [13, 14, 15, 16, 17, 18, 19], [20, 21, 22, 23, 24, 25, 26], [27, 28, 29, 30, 0, 0, 0]], [[0, 0, 0, 0, 1, 2, 3], [4, 5, 6, 7, 8, 9, 10], [11, 12, 13, 1
4, 15, 16, 17], [18, 19, 20, 21, 22, 23, 24], [25, 26, 27, 28, 29, 30, 31]], [[1, 2, 3, 4, 5, 6, 7], [8, 9, 10, 11, 12, 13, 14], [15, 16, 17, 18, 19, 20, 21], [22, 23, 24, 25, 26, 27, 28], [29, 30, 0, 0, 0, 0, 0]]
, [[0, 0, 1, 2, 3, 4, 5], [6, 7, 8, 9, 10, 11, 12], [13, 14, 15, 16, 17, 18, 19], [20, 21, 22, 23, 24, 25, 26], [27, 28, 29, 30, 31, 0, 0]], [[0, 0, 0, 0, 0, 1, 2], [3, 4, 5, 6, 7, 8, 9], [10, 11, 12, 13, 14, 15,
16], [17, 18, 19, 20, 21, 22, 23], [24, 25, 26, 27, 28, 29, 30], [31, 0, 0, 0, 0, 0, 0]], [[0, 1, 2, 3, 4, 5, 6], [7, 8, 9, 10, 11, 12, 13], [14, 15, 16, 17, 18, 19, 20], [21, 22, 23, 24, 25, 26, 27], [28, 29, 30,
 0, 0, 0, 0]], [[0, 0, 0, 1, 2, 3, 4], [5, 6, 7, 8, 9, 10, 11], [12, 13, 14, 15, 16, 17, 18], [19, 20, 21, 22, 23, 24, 25], [26, 27, 28, 29, 30, 31, 0]], [[0, 0, 0, 0, 0, 0, 1], [2, 3, 4, 5, 6, 7, 8], [9, 10, 11,
12, 13, 14, 15], [16, 17, 18, 19, 20, 21, 22], [23, 24, 25, 26, 27, 28, 29], [30, 0, 0, 0, 0, 0, 0]]]

我該如何做才能只保留大於 0 的項目，例如在這種情況下：

[0, 0, 1, 2, 3, 4, 5]

成為：

[1, 2, 3, 4, 5]

Answer 1

只需在附加之前添加一個 if 語句：

saptamani = []
for months in range(1, 12):
    luna = [m for m in calendar.monthcalendar(2020, months) if m > 0]
    saptamani.append(luna)

print(saptamani)

或者 - 作為列表理解：

saptamani = [luna 
             for months in range(1, 12) 
             for luna in [m for m in calendar.monthcalendar(2020, months) if m > 0]]

Answer 2

saptamani = []
for months in range(1, 12):
    luna = calendar.monthcalendar(2020, months)
    for i in luna:
        prepare = [m for m in i if m > 0]
        saptamani.append(new_w)

print(saptamani)

@Jan，你的回答幫助了我。 這就是它的工作原理