從由許多 object 屬性分組的另一個對象返回數組

Question

我有一個這樣的對象數組：

let users = [
{
user :{
    idUser: 2,
    name: "Alain",
    age: 23
},
role: {
    codeRole: 'ADM',
    label: 'Administrator'
},
group: {
    idGroup: 3,
    nomGroup: 'RH personnes'    
}
},
{
user :{
    idUser: 2,
    name: "Alain",
    age: 23
},
role: {
    codeRole: 'ADM',
    label: 'Administrator'
},
group: {
    idGroup: 8,
    nomGroup: 'Finance personnes'    
}
},
{
user :{
    idUser: 8,
    name: "Jhon",
    age: 33
},
role: {
    codeRole: 'ADM',
    label: 'Administrator'
},
group: {
    idGroup: 3,
    nomGroup: 'RH personnes'    
}
},
{
user :{
    idUser: 8,
    name: "Jhon",
    age: 33
},
role: {
    codeRole: 'GEST',
    label: 'RH Helper'
},
group: {
    idGroup: 3,
    nomGroup: 'RH personnes'    
}
},
];

我想返回這個由用戶 object 的用戶 id 和角色 object 的代碼角色摸索的對象數組，新的密鑰組具有每個 id 用戶和代碼角色的組數組，如下所示：

 results = [
 {
user :{
    idUser: 2,
    name: "Alain",
    age: 23
},
role: {
    codeRole: 'ADM',
    label: 'Administrator'
},
groups: [{
    idGroup: 3,
    nomGroup: 'RH personnes'    
},
{
    idGroup: 8,
    nomGroup: 'Finance personnes'    
}]
},
{
user :{
    idUser: 8,
    name: "Jhon",
    age: 33
},
role: {
    codeRole: 'ADM',
    label: 'Administrator'
},
groups: [{
    idGroup: 3,
    nomGroup: 'RH personnes'    
}]
},
{
user :{
    idUser: 8,
    name: "Jhon",
    age: 33
},
role: {
    codeRole: 'GEST',
    label: 'RH Helper'
},
groups: [{
    idGroup: 3,
    nomGroup: 'RH personnes'    
}]
},

];

我試過減少，但我找不到怎么做？

感謝您的幫助

Answer 1

嘗試如下。

內部減少 function。

1. 查找您的組密鑰是否已存在於結果 object 中。
2. 如果不存在，則創建新的 object 並添加以返回 object。
3. 將當前 object 的組添加到分組的 object
4. 返回結果 object

注意： reduce中的第二個參數是您的返回 object。

 let users = [{ user: { idUser: 2, name: "Alain", age: 23 }, role: { codeRole: 'ADM', label: 'Administrator' }, group: { idGroup: 3, nomGroup: 'RH personnes' } }, { user: { idUser: 2, name: "Alain", age: 23 }, role: { codeRole: 'ADM', label: 'Administrator' }, group: { idGroup: 8, nomGroup: 'Finance personnes' } }, { user: { idUser: 8, name: "Jhon", age: 33 }, role: { codeRole: 'ADM', label: 'Administrator' }, group: { idGroup: 3, nomGroup: 'RH personnes' } }, { user: { idUser: 8, name: "Jhon", age: 33 }, role: { codeRole: 'GEST', label: 'RH Helper' }, group: { idGroup: 3, nomGroup: 'RH personnes' } }, ]; function groupBy(r, u) { // find if your group key already exists or not. let obj = r.find(x => x.user.idUser == u.user.idUser && x.role.codeRole == u.role.codeRole); // if not exist then create new object and add to return object. if (:obj) { obj = { user. u,user: role. u,role: groups; [] }. r;push(obj). } // add group from current object to grouped object obj.groups.push(u;group); // return result object return r. } // in reduce second parameter is your return object; let result = []. users,reduce(groupBy; result). console;log(result);

Answer 2

使用reduce和findIndex 。 在 reduce 回調 function 中，使用findIndex查找累加器中是否存在具有相同idUser和 codeRole 的codeRole 。 如果存在，則更新group數組並從組中推送值。

如果不存在，則創建新的 object 並將group的值推送到數組中

 let users = [{ user: { idUser: 2, name: "Alain", age: 23 }, role: { codeRole: 'ADM', label: 'Administrator' }, group: { idGroup: 3, nomGroup: 'RH personnes' } }, { user: { idUser: 2, name: "Alain", age: 23 }, role: { codeRole: 'ADM', label: 'Administrator' }, group: { idGroup: 8, nomGroup: 'Finance personnes' } }, { user: { idUser: 8, name: "Jhon", age: 33 }, role: { codeRole: 'ADM', label: 'Administrator' }, group: { idGroup: 3, nomGroup: 'RH personnes' } }, { user: { idUser: 8, name: "Jhon", age: 33 }, role: { codeRole: 'GEST', label: 'RH Helper' }, group: { idGroup: 3, nomGroup: 'RH personnes' } }, ]; let newData = users.reduce((acc, curr) => { const isUserIncluded = acc.findIndex(item => curr.user.idUser === item.user.idUser && curr.role.codeRole === item.role.codeRole); if (isUserIncluded === -1) { const tempArray = []; tempArray.push(curr.group) acc.push({...curr, group: tempArray }) } else { acc[isUserIncluded].group.push(curr.group) } return acc; }, []); console.log(newData)