[英]how to console log or alert the data after posted in the server
我正在我的服務器上發布反饋數據,並希望在警報中查看發布的數據。
export const postFeedback = (
firstname,
lastname,
telnum,
email,
agree,
contactType,
message
) => (dispatch) => {
const newFeedback = {
firstname: firstname,
lastname: lastname,
telnum: telnum,
email: email,
agree: agree,
contactType: contactType,
message: message,
};
newFeedback.date = new Date().toISOString();
return fetch(baseUrl + 'feedback', {
method: 'POST',
body: JSON.stringify(newFeedback),
headers: {
'Content-Type': 'application/json',
},
credentials: 'same-origin',
})
.then(
(response) => {
if (response.ok) {
return response;
} else {
var error = new Error(
'Error ' + response.status + ': ' + response.statusText
);
error.response = response;
throw error;
}
},
(error) => {
throw error;
}
)
.then((response) => response.json())
.then((response) => dispatch(addFeedback(response)))
.then((response) => alert(response))
.catch((error) => {
console.log('post feedback', error.message);
alert('Your feedback could not be posted\nError: ' + error.message);
});
};
數據已正確發布,但在警報中我只看到[object Object]
為什么? 發布到服務器后如何控制台日志或警告數據?
如果有人幫助我解決這個問題,我衷心感謝。
您可以使用JSON.stringify(obj)
記錄錯誤,因為alert
僅顯示文本
您需要將 object 解析為字符串,使用JSON.stringify(x)
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/JSON/stringify
[object Object]
是 object 的字符串化表示。
任何一個
做alert(JSON.stringify(error.message))
或者
做console.log(error.message)
嘗試將 JSON 轉換為字符串,你可以試試這個。
export const postFeedback = (
firstname,
lastname,
telnum,
email,
agree,
contactType,
message
) => (dispatch) => {
const newFeedback = {
firstname: firstname,
lastname: lastname,
telnum: telnum,
email: email,
agree: agree,
contactType: contactType,
message: message,
};
newFeedback.date = new Date().toISOString();
return fetch(baseUrl + 'feedback', {
method: 'POST',
body: JSON.stringify(newFeedback),
headers: {
'Content-Type': 'application/json',
},
credentials: 'same-origin',
})
.then(
(response) => {
if (response.ok) {
return response;
} else {
var error = new Error(
'Error ' + response.status + ': ' + response.statusText
);
error.response = response;
throw error;
}
},
(error) => {
throw error;
}
)
.then((response) => response.json())
.then((response) => dispatch(addFeedback(response)))
.then((response) => alert(JSON.stringify(response)))
.catch((error) => {
console.log('post feedback', error.message);
alert('Your feedback could not be posted\nError: ' + error.message);
});
};
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