[英]Grouping based on preferences keep returning null value
public class HomeroomMix {
public void calculate(String className, int number) {
List<PeopleClass> people = Arrays.asList(
new PeopleClass("DE", "male"),
new PeopleClass("DE", "female"),
new PeopleClass("DE", "n/a"),
new PeopleClass("UK", "female"),
new PeopleClass("UK", "female"),
new PeopleClass("UK", "female"),
new PeopleClass("JP", "trans"),
new PeopleClass("JP", "male")
);
int number_of_groups = number;
Function<PeopleClass, String> discriminator = PeopleClass::getGender;
AtomicInteger index = new AtomicInteger();
List<List<PeopleClass>> groups = new ArrayList<>(people.stream()
.sorted(Comparator.comparing(discriminator))
.collect(Collectors.groupingBy(e -> index.getAndIncrement() % number_of_groups))
.values());
groups.forEach(System.out::println);
}
這是我的人 class
public PeopleClass(String nationality, String gender) {
this.gender = gender;
this.nationality = nationality;
}
public String getNationality() {
return nationality;
}
public void setNationality(String nationality) {
this.nationality = nationality;
}
public String getGender() {
return gender;
}
public void setGender(String gender) {
this.gender = gender;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getHomeRoom() {
return homeRoom;
}
public void setHomeRoom(String homeRoom) {
this.homeRoom = homeRoom;
}
@Override
public String toString() {
return name;
}
}
我正在嘗試按偏好對人們進行分組,我最初是在 greenfoot 上編寫的,它運行良好。 但是,我最近想用 javafx 將它嵌入到 intellij 的一個項目中。 當我測試時,它系統 output null。 雖然我也計划循環一個對象列表而不是在列表中添加每個對象 - 我試過了,它一直在發送空值。
[null, null, null]
[null, null, null]
[null, null]
我想打印類似的東西
[person1, person3, person 6]
[person 5, person 2, person 4]
[person 7, person 8]
為什么要對值進行排序並使用 AtomicInteger? 像這樣試試。
首先,我添加了一些名稱
int i = 1;
for (PeopleClass p : people) {
p.setName("Person" + i++);
}
然后我按性別分組
List<List<PeopleClass>> groups = new ArrayList<>(people
.stream()
.collect(Collectors
.groupingBy(PeopleClass::getGender))
.values());
並打印出來。
groups.forEach(System.out::println);
這是結果
[Person3:n/a]
[Person2:female, Person4:female, Person5:female, Person6:female]
[Person1:male, Person8:male]
[Person7:trans]
注意:你的人 class 缺少一些東西,比如
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