嘗試從數組調用返回字符串時出錯

Question

此代碼返回錯誤和第二個“else if”語句：

 function likes(names) { if (names.length == 0) { return "no one likes this" } else if (names.length == 1) { return names[0] + " likes this" }; // the above is running fine if I remove the second to else if statements. else if (names.length == 2) { return names[0] + " and " /*error starts here*/ + names[0] + " like this" }; else if (names.length == 3) { return names[0] + ", " + names[1] + " and " + names[2] + " like this" }; else if (names.lenght > 3) { return names[0] + ", " + names[1] + " and " + names.length - 1 + "others like this}; } console.log(likes(["james", "pete"]))

我想這是我如何將琴弦連接在一起的問題，但我似乎無法弄清楚。

不好意思，還在學習。 感謝任何反饋。

Answer 1

您正在添加; 在else if它破壞了代碼。 同樣在這一行中沒有關閉"

return names[0] + ", " + names[1] + " and  " + names.length - 1 + "others like this}

 function likes(names) { if (names.length == 0) { return "no one likes this" } else if (names.length == 1) { return names[0] + " likes this" } // the above is running fine if I remove the second to else if statements. else if (names.length == 2) { return names[0] + " and " /*error starts here*/ + names[0] + " like this" } else if (names.length == 3) { return names[0] + ", " + names[1] + " and " + names[2] + " like this" } else if (names.lenght > 3) { return names[0] + ", " + names[1] + " and " + names.length - 1 + "others like this" } } console.log(likes(["james", "pete"]))

Answer 2

問題：

1. 每個 if 語句末尾的不需要的分號};
2. 最后一條語句沒有正確關閉"

 function likes(names) { if (names.length == 0) { return "no one likes this" } else if (names.length == 1) { return names[0] + " likes this" } else if (names.length == 2) { return names[0] + " and " /*error starts here*/ + names[0] + " like this" } else if (names.length == 3) { return names[0] + ", " + names[1] + " and " + names[2] + " like this" } else if (names.lenght > 3) { return names[0] + ", " + names[1] + " and " + (names.length - 1) + "others like this" } } console.log(likes(["james", "pete"]))