[英]SQL Query to get the json array values by comma separated
我有以下 Json object。 我需要用逗號(,)分隔的任務名稱。
{
"Model": [
{
"ModelName": "Test Model",
"Object": [
{
"ID": 1,
"Name": "ABC",
"Task" : [
{
TaskID : 1222,
Name: "TaskA"
},
{
TaskID : 154,
Name: "TaskB"
}
]
},
{
"ID": 11,
"Name": "ABCD",
"Task" : [
{
TaskID : 222,
Name: "TaskX"
},
{
TaskID : 234,
Name: "TaskY"
}
]
},
]
}]}
預期的 Output 應在下表中。 我需要任務名稱應該用逗號分隔。
ModelName ObjectID ObjectName TaskName
Test Model 1 ABC TaskA, TaskB
Test Model 11 ABCD TaskX, TaskY
我嘗試了以下查詢。 但我不知道如何對任務名稱進行分組。
SELECT S1.ModelName,
S2.ID AS ObjectID,
S2.Name AS ObjectName,
S3.TaskName
FROM TableA
CROSS APPLY OPENJSON(JsonData)
WITH (Model NVARCHAR(MAX) '$.Model[0]' AS JSON) S1
CROSS APPLY OPENJSON (S1.Model)
WITH (Object NVARCHAR(MAX) '$.Object' AS JSON,
ID INT '$.ID',
Name NVARCHAR(250) '$.Name') S2
CROSS APPLY OPENJSON (S2.Object)
WITH (Task NVARCHAR(MAX) '$.Task' AS JSON ,
TaskName NVARCHAR(MAX) '$.TaskName') S3
將 json 更正為有效格式,這里是 SQL 查詢,用於您所需的 output。 以下查詢在Oracle 編譯器中編譯並運行良好
SELECT * FROM JSON_TABLE(
'{"Model":[{"ModelName":"Test Model","Object":[{"ID":1,"Name":"ABC","Task":[{"TaskID":1222,"Name":"TaskA"},{"TaskID":154,"Name":"TaskB"}]},{"ID":11,"Name":"ABCD","Task":[{"TaskID":222,"Name":"TaskX"},{"TaskID":234,"Name":"TaskY"}]}]}]}',
'$.Model[*]'
COLUMNS (
-- L_MODEL_ROWNUM FOR ORDINALITY,
L_MODEL_NAME VARCHAR2(10) PATH '$.ModelName',
NESTED PATH '$.Object[*]' COLUMNS (
--L_OBJECT_ROWNUM FOR ORDINALITY,
L_OBJECT_ID NUMBER PATH '$.ID',
L_OBJECT_NAME VARCHAR2(10) PATH '$.Name',
L_TASK_NAME VARCHAR2(100) FORMAT JSON WITH WRAPPER PATH '$.Task[*].Name'
)
)
)
這是在SQL Server 2019上運行的查詢,
DECLARE @JSONDATA NVARCHAR(MAX);
SET
@JSONDATA = N'{"Model":[{"ModelName":"Test Model","Object":[{"ID":1,"Name":"ABC","Task":[{"TaskID":1222,"Name":"TaskA"},{"TaskID":154,"Name":"TaskB"}]},{"ID":11,"Name":"ABCD","Task":[{"TaskID":222,"Name":"TaskX"},{"TaskID":234,"Name":"TaskY"}]}]}]}';
WITH TASK AS
(
SELECT
MODEL,
ID,
NAME,
TASK_NAME
FROM
OPENJSON(@JSONDATA) WITH (MODELS NVARCHAR(MAX) '$.Model' AS JSON) CROSS APPLY OPENJSON(MODELS) WITH (MODEL NVARCHAR(80) '$.ModelName', OBJECTS NVARCHAR(MAX) '$.Object' AS JSON) CROSS APPLY OPENJSON(OBJECTS ) WITH (ID INT '$.ID', NAME NVARCHAR(250) '$.Name', TASKS NVARCHAR(MAX) '$.Task' AS JSON ) CROSS APPLY OPENJSON (TASKS) WITH (TASK_NAME NVARCHAR(80) '$.Name')
)
SELECT DISTINCT
MODEL AS MODELNAME,
ID AS OBJECTID,
NAME AS OBJECTNAME,
STUFF((
SELECT
',' + [TASK_NAME]
FROM
TASK T1
WHERE
T1.[ID] = T2.[ID] FOR XML PATH('')), 1, 1, '') AS TASKNAME
FROM
TASK T2;
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