Jackson scala模塊：反序列化案例object枚舉

Question

我正在使用 Jackson scala 模塊，我需要序列化/反序列化案例 object 枚舉。 序列化工作正常，但是當反序列化返回值時，我得到com.fasterxml.jackson.databind.exc.InvalidDefinitionException 。 有辦法讓它工作嗎？ 我想避免使用“經典”scala 枚舉，因為我將失去定義枚舉層次結構的能力。

用於測試的代碼：

import com.fasterxml.jackson.annotation.JsonValue
import com.fasterxml.jackson.databind.{DeserializationFeature, ObjectMapper}
import com.fasterxml.jackson.module.scala.DefaultScalaModule
import com.fasterxml.jackson.module.scala.experimental.ScalaObjectMapper


sealed trait Operations { @JsonValue def jsonValue: String }

case object Foo extends Operations { override def jsonValue: String = "Foo" }

case object Bar extends Operations { override def jsonValue: String = "Bar" }


sealed trait RichOperations extends Operations

case object Baz extends RichOperations { override def jsonValue: String = "Baz" }


object JsonUtils extends App {

  val jsonMapper = new ObjectMapper() with ScalaObjectMapper
  jsonMapper.registerModule(DefaultScalaModule)
    .configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false)

  def toJson(value: Any): String = jsonMapper.writeValueAsString(value)

  def fromJson[T: Manifest](json: String): T = jsonMapper.readValue[T](json)


  println(toJson(Foo)) // "Foo"
  println(toJson(Bar)) // "Bar"
  println(toJson(Baz)) // "Baz"
  println(fromJson[Operations](toJson(Foo))) // throws InvalidDefinitionException
  println(fromJson[Operations](toJson(Bar)))
  println(fromJson[RichOperations](toJson(Baz)))
}

Answer 1

我解決了定義自定義反序列化器的問題。

import com.fasterxml.jackson.core.JsonParser
import com.fasterxml.jackson.databind.{DeserializationContext, JsonDeserializer}


class OperationsDeserializer extends JsonDeserializer[Operations] {

  override def deserialize(p: JsonParser, ctxt: DeserializationContext): Operations = {
    p.getValueAsString match {
      case Foo.jsonValue => Foo
      case Bar.jsonValue => Bar
      case value => throw new IllegalArgumentException(s"Undefined deserializer for value: $value")
    }
  }
}


class RichOperationsDeserializer extends JsonDeserializer[Operations] {

  override def deserialize(p: JsonParser, ctxt: DeserializationContext): Operations = {
    p.getValueAsString match {
      case Foo.jsonValue => Foo
      case Bar.jsonValue => Bar
      case Baz.jsonValue => Baz
      case value => throw new IllegalArgumentException(s"Undefined deserializer for value: $value")
    }
  }
}

此外，由於在匹配/案例中需要穩定的標識符，我將jsonValue從def更改為val ：不幸的是，這需要在 object 枚舉的每種情況下聲明@JsonValue注釋。

import com.fasterxml.jackson.databind.annotation.JsonDeserialize


@JsonDeserialize(using = classOf[OperationsDeserializer])
sealed trait Operations { val jsonValue: String }

case object Foo extends Operations { @JsonValue override val jsonValue: String = "Foo" }

case object Bar extends Operations { @JsonValue override val jsonValue: String = "Bar" }


@JsonDeserialize(using = classOf[RichOperationsDeserializer])
sealed trait RichOperations extends Operations

case object Baz extends RichOperations { @JsonValue override val jsonValue: String = "Baz" }