如何聲明指向成員模板 function 的指針？

Question

struct S
{
    template <auto> void F(){};
};

S s;
void (S::* pmf)()=s.F<true>;

編譯錯誤，如何解決？ 謝謝你的幫助。

Answer 1

You should use the class name to qualify the member function, and there's no implicit conversion from member function to member function pointer, so use operator& explicitly. 例如

void (S::* pmf)() = &S::F<true>;

居住