成功滿足條件時如何停止for循環迭代？

Question

所以，我正在編寫手板球腳本，我想在用戶選擇的數字和 CPU 選擇的數字相等時停止“for”循環迭代，如果它不相等，它應該繼續迭代，直到它沒有達到最終范圍的值

for i in range(1,7):
    print("Ball %d"%i)
    user_choice =int(input("Enter a number between 1 to 6 --> "))
    cpu_choice=random.randint(1,6)

    if user_choice < 7:
        print("CPU picked --> ",cpu_choice)
        run=cpu_choice+run

    if user_choice == cpu_choice:
        print("User is OUT!!")
        run -= cpu_choice
        print("Runs = %d \t Over = %d.%d\n"%(run,i//6,i%6))
        break
        print("Runs = %d \t Over = %d.%d\n"%(run,i//6,i%6))

    else:
        print("\nWRONG CHOICE!! %d ball is cancelled.\n"%i)
        break

Answer 1

我可能在你的問題中遺漏了一些東西，但看起來你已經明白了。 break將強制for循環退出。 因此，如果您將中斷語句包裝在條件門（ if語句）中，則可以設置中斷必須滿足的條件。

想到這樣的事情：

# Calculate the CPU's Random Integer ONCE
cpu_choice=random.randint(1,6)

# Iteratively Ask User for Input and Validate
for i in range(1,7):
    # Capture Input from User
    user_choice =int(input("Enter a number between 1 to 6 --> "))
    # Verify Input in Specific Range
    if user_choice not in range(1,7):
        print("{} is not in the valid range. Try again.".format(user_choice))
    else:
        # Check if User Input Matches CPU's Selection
        if user_choice == cpu_choice:
            print("You've got the right number! The number was: {}".format(user_choice))

            break  # break out of the `for` loop!

        # Not Correct Input from User
        else:
            print("{} is not the correct number. Try again.".format(user_choice))

同樣，您似乎已經以某種方式得出了這個答案。 你是在問別的嗎？