[英]Count Total Indexes of Array in PHP
我有一個具有以下結構的數組:
Array
(
[DigitalAssets] => Array
(
[0] => Array
(
[PartNumber] => 0276S-4
[Link] => https://1ddf4b1b856a39e33863-d785dc0e3b62b5e0ef07f55db00b0659.ssl.cf2.rackcdn.com/Holley/0576s-4.jpg
[AssetTypeCode] => P04
[FileName] => 0576s-4.jpg
[RecordModifiedDate] => 2020-05-13T18:59:10.28
)
[1] => Array
(
[PartNumber] => 0437S-4
[Link] => https://1ddf4b1b856a39e33863-d785dc0e3b62b5e0ef07f55db00b0659.ssl.cf2.rackcdn.com/Holley/0437s-4.jpg
[AssetTypeCode] => P04
[FileName] => 0437s-4.jpg
[RecordModifiedDate] => 2020-05-13T18:59:11.687
)
[2] => Array
(
[PartNumber] => 0574S-4
[Link] => https://1ddf4b1b856a39e33863-d785dc0e3b62b5e0ef07f55db00b0659.ssl.cf2.rackcdn.com/Holley/0574s-4.jpg
[AssetTypeCode] => P04
[FileName] => 0574s-4.jpg
[RecordModifiedDate] => 2020-05-13T18:59:12.593
)
我想計算數組的總索引,以便相應地運行循環。 我使用了 Count($array) 和 Count ($array,RECURSIVE) 但它無法返回正確的索引總數。
只能指導一下如何做到這一點?
謝謝
如果要計算DigitalAssets
直接子項,可以這樣做count($array['DigitalAssets'])
這里有一些測試count
應該如何工作。
代碼是:
$test = array
(
'DigitalAssets' => array
(
0 => array(
'PartNumber' => '0276S-4',
'Link' => 'https://1ddf4b1b856a39e33863-d785dc0e3b62b5e0ef07f55db00b0659.ssl.cf2.rackcdn.com/Holley/0576s-4.jpg',
'AssetTypeCode' => 'P04',
'FileName' => '0576s-4.jpg',
'RecordModifiedDate' => '2020-05-13T18:59:10.28'
),
1 => array(
'PartNumber' => '0437S-4',
'Link' => 'https://1ddf4b1b856a39e33863-d785dc0e3b62b5e0ef07f55db00b0659.ssl.cf2.rackcdn.com/Holley/0437s-4.jpg',
'AssetTypeCode' => 'P04',
'FileName' => '0437s-4.jpg',
'RecordModifiedDate' => '2020-05-13T18:59:11.687'
),
2 => array
(
'PartNumber' => '0574S-4',
'Link' => 'https://1ddf4b1b856a39e33863-d785dc0e3b62b5e0ef07f55db00b0659.ssl.cf2.rackcdn.com/Holley/0574s-4.jpg',
'AssetTypeCode' => 'P04',
'FileName' => '0574s-4.jpg',
'RecordModifiedDate' => '2020-05-13T18:59:12.593'
)
)
);
echo count($test['DigitalAssets'])." ".count($test['DigitalAssets'], 0)." ".count($test['DigitalAssets'], 1);
exit();
結果在我的情況下: 3 3 18
這意味着在我的情況下,計數mode
默認設置為 0,因此我只會計算第一級。 如果我將模式設置為 1,我也會計算所有嵌套項目。 這應該為您解決問題。
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