如何僅從嵌套的 for 循環中打印一次結果

Question

我正在嘗試創建一個自定義條形圖，用戶可以在其中輸入他們想用來創建每個條形的條數、條形大小和符號。

public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);

        System.out.println("How many bars would you like to display?");
        int num_bars = scan.nextInt();

        int [] bars = new int[num_bars];
        String [] symbol = new String[num_bars];

        System.out.println("Specify the sizes of the bars: ");
        for(int i = 0; i < bars.length; i++) {
            bars[i] = scan.nextInt();
        }

        System.out.println("Specify the symbols to be used for the bars:");
        for(int i = 0; i < symbol.length; i++) {
            symbol[i] = scan.next();
        }

        int number = 1;
        for(int bar : bars) {
            System.out.print("\n" + number);
            for (String sym : symbol) {
                for (int size = 0; size < bar; size ++ ) {
                     System.out.print(sym +" "); 
            }
        System.out.println(" ");
        number++;
        }
        }   

    }
}

我得到的結果是這樣顯示的：

How many bars would you like to display?
2
Specify the sizes of the bars: 
8
4
Specify the symbols to be used for the bars:
%
#

1% % % % % % % %  
# # # # # # # #  

3% % % %  
# # # #  

但我的目標是：

1 % % % % % % % %  
2 # # # #  

有人可以幫幫我嗎？

Answer 1

無需遍歷 symbol[] 數組。 這是多余的，因為您可以使用其索引打印每個柱的符號。

public static void main(String[] args) {
    Scanner scan = new Scanner(System.in);

    System.out.println("How many bars would you like to display?");
    int num_bars = scan.nextInt();

    int[] bars = new int[num_bars];
    String[] symbol = new String[num_bars];

    System.out.println("Specify the sizes of the bars: ");
    for (int i = 0; i < bars.length; i++) {
        bars[i] = scan.nextInt();
    }

    System.out.println("Specify the symbols to be used for the bars:");
    for (int i = 0; i < symbol.length; i++) {
        symbol[i] = scan.next();
    }

    int number = 1;
    for (int bar : bars) {
        System.out.print("\n" + number + " ");
        for (int size = 0; size < bar; size++) {
            System.out.print(symbol[number - 1] + " ");
        }
        System.out.println(" ");
        number++;
    }
}

Answer 2

您需要將代碼更改為以下內容，因為您在下一個數字之前執行 number++ 並且無需再次迭代符號數組，只需使用數字 integer 值。 如下請見：

       for (int bar : bars) {
        System.out.print("\n" + number);
        //for (String sym : symbol) {
            for (int size = 0; size < bar; size++) {
                System.out.print(symbol[number - 1] + " ");
        //              }
        //             System.out.println(" ");
        }
        number++;
    }