如何在 oracle SQL 開發人員中插入數據

Question

我想在 Oracle SQL Developer 中插入數據。 在客戶端，我的意思是 web 頁面，它顯示數據已插入，但是當我在 SQL Developer 中檢查時，沒有插入數據。

我看到了這個錯誤信息：

Caused by: Error: 1400, Position: 88, Sql = INSERT INTO noticebook(NUM, NAME, EMAIL, CONTENTS) VALUES(BOOK_NUM.NEXTVAL, :1, :2, :3 ), OriginalSql = INSERT INTO noticebook(NUM, NAME , EMAIL, 內容) 值(BOOK_NUM.NEXTVAL, ?, ?, ?), 錯誤信息 = ORA-01400: NULL ("C##YESMONDAY"."NOTICEBOOK")。

似乎查詢不正確，但我找不到問題所在。

查看頁面 (main.jsp)

<body>
<h1>Notice Board</h1>
<div id="wrap">
    <div id="wrap_form">
        <form action="mainWritePro.jsp" method="post">
            <table>
                <tr>
                    <td></td>
                    <td><input type="text" name="name" placeholder="TITLE "></td>
                </tr>
                <tr>
                    <td></td>
                    <td><input type="text" name="email" placeholder="EMAIL "></td>
                </tr>
                <tr>
                    <td> </td>
                    <td>
                        <textarea rows="15" cols="50" placeholder="INQUIRY"></textarea>
                    </td>
                </tr>
                <tr class="send">
                    <td colspan="2" align="center"><input type="submit" name="" value="SEND" ></td>
                </tr>
            </table>
        </form>
    </div>
    <ul>
        <li><a href="#">DELETE</a></li>
        <li><a href="#">UPDATE</a></li>
        <li><a href="#">LIST</a></li>
    </ul>
</div>

公告板VO.java

package edu.kosta.vistorsPrac;

public class noticeBoardVO { // Model
    private int num; private String name, email, contents;
    public noticeBoardVO() {} 

    public int getNum() {   return num; }
    public void setNum(int num) {   this.num = num; }
    public String getName() {   return name; }
    public void setName(String name) {  this.name = name; }
    public String getEmail() {  return email; }
    public void setEmail(String email) {    this.email = email; }
    public String getContents() {   return contents; }
    public void setContents(String contents) {  this.contents = contents; }
}

noticeBoardDAO.java 我假設錯誤發生在這里..

public class noticeBoardDAO {// Controller

// DB Connection & Open
public static Connection loadOracleDriver() {
    Connection conn = null;
    try {
        conn = ConnectionHelper.getConnection("oracle");
    } catch (Exception e) {
        e.printStackTrace();
    }
    return conn;
}

// INSERT
public static void insert(Connection conn, noticeBoardVO vo) {
    StringBuffer sb = new StringBuffer();
    PreparedStatement pstmt = null;
    try {
        conn = ConnectionHelper.getConnection("oracle");
        sb.append("INSERT INTO noticebook(NUM, NAME, EMAIL, CONTENTS) ");
        sb.append(" VALUES(BOOK_NUM.NEXTVAL, ?, ?, ?) ");
        System.out.println(sb.toString());
        pstmt = conn.prepareStatement(sb.toString());
        pstmt.setString(1, vo.getName());
        pstmt.setString(2, vo.getEmail());
        pstmt.setString(3, vo.getContents());
        pstmt.executeUpdate(); //

    } catch (Exception e) {
        e.printStackTrace();
    }
}

mainWritePro.jsp（用戶點擊SEND btn后顯示）

<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>Insert Page</title>
<link rel="stylesheet" type="text/css" href="../css/main.css">
</head>
<%
        request.setCharacterEncoding("utf-8");
%>
<body>

    <jsp:useBean id="vo" class="edu.kosta.vistorsPrac.noticeBoardVO"></jsp:useBean>
    <jsp:setProperty property="*" name="vo" />

    <%
    Connection conn = noticeBoardDAO.loadOracleDriver();
    noticeBoardDAO.insert(conn, vo);
    %>

    <h1>Successfully Inserted !</h1>
    <ul>
        <li><a href="#">DELETE</a></li>
        <li><a href="#">UPDATE</a></li>
        <li><a href="#">LIST</a></li>
    </ul>
</body>
</html>

Answer 1

ORA-01400: 無法將 NULL 插入 ("SCHEMA"."TABLE_NAME"."COLUMN_NAME")

您的 textarea 未設置名稱，所以我認為您的內容值為 null。

如何在 oracle SQL 開發人員中插入數據

問題描述

1 個解決方案

解決方案1
0 已采納 2020-05-20 02:12:48

如何在 oracle SQL 開發人員中插入數據

問題描述

1 個解決方案

解決方案1 0 已采納 2020-05-20 02:12:48

解決方案1
0 已采納 2020-05-20 02:12:48