在 Mulesoft Dataweave 2.0 中展開數組

Question

我有一組扁平的客戶，但找不到合適的方法（方式）來展開它，以便每個客戶及其年齡都嵌套。

輸入

{
 "1st Customer": "2216",
 "Age": "90",
 "2nd Customer": "2231",
 "Age": "90",
 "3rd Customer": "2249",
 "Age": "120",
 "4th Customer": "2302",
 "Age": "150",
 "5th Customer": "",
 "Age": ""
}

OUTPUT

{
 "customers": [
  {
   "CustomerSeq": "1",
   "CustomerID": "2216",
   "Age": 90,
  },
  {
   "CustomerSeq": "2",
   "CustomerID": "2231",
   "Age": 90,
  },
  {
   "CustomerSeq": "3",
   "CustomerID": "2249",
   "Age": 120,
  },
  {
   "CustomerSeq": "5",
   "CustomerID": "2302",
   "Age": 150,
  }
 ]
}

Answer 1

在 Mule 中有一個很好的 function ： divideBy 。 它將從 object 中拆分出一組值，然后可以創建請求的 object：

%dw 2.0
var x={
 "1st Customer": "2216",
 "Age": "90",
 "2nd Customer": "2231",
 "Age": "90",
 "3rd Customer": "2249",
 "Age": "120",
 "4th Customer": "2302",
 "Age": "150",
 "5th Customer": "",
 "Age": ""
}
var keys=x pluck $$
var values=x pluck $
import * from dw::core::Arrays
output application/dw
---
values divideBy 2 map (item,index) -> 
 {
    CustomerSeq:index+1,
    CustomerID:item[0],
    Age:item[1]
 }

output

[
  {
    CustomerSeq: 1,
    CustomerID: "2216",
    Age: "90"
  }, 
  {
    CustomerSeq: 2,
    CustomerID: "2231",
    Age: "90"
  }, 
  {
    CustomerSeq: 3,
    CustomerID: "2249",
    Age: "120"
  }, 
  {
    CustomerSeq: 4,
    CustomerID: "2302",
    Age: "150"
  }, 
  {
    CustomerSeq: 5,
    CustomerID: "",
    Age: ""
  }
]

Answer 2

非常感謝 Alex The divideBy正是我想要的

解決方案[包括刪除空值]：

 %dw 2.0 output application/json import * from dw::core::Objects --- customers: ((payload filterObject ((value, key, index) -> value,= "")) divideBy 2) map ( (pCustomer: indexOfpCustomer) -> { CustomerSeq,indexOfpCustomer+1: CustomerID, pCustomer[0]: Age: pCustomer[1] })