如果日期匹配，則將項目推送到數組中 - JavaScript/TypeScript

Question

短路數組以顯示它們的日期，就像我一樣 - 徒步旅行，2020 年 5 月 10 日購物和 2020 年 5 月 10 日徒步旅行，足球，其他日期類似。

 const items = [
 {title: 'Hiking', date: new Date('2020-05-10')},
 {title: 'Shopping', date: new Date('2020-05-10')},
 //
 {title: 'Hiking', date: new Date('2020-05-22')},
 {title: 'Football', date: new Date('2019-05-22')},
 //
 {title: 'Football', date: new Date('2020-05-28')},
 {title: 'Hiking', date: new Date('2020-05-28')},
 {title: 'Cricket', date: new Date('2020-05-28')},
];

Answer 1

嘗試這個

 let items = [ {title: 'Hiking', date: new Date('2020-05-10')}, {title: 'Shopping', date: new Date('2020-05-10')}, {title: 'Hiking', date: new Date('2020-05-22')}, {title: 'Football', date: new Date('2019-05-22')}, {title: 'Football', date: new Date('2020-05-28')}, {title: 'Hiking', date: new Date('2020-05-28')}, {title: 'Cricket', date: new Date('2020-05-28')}, ]; items.sort(function(a,b){ return a.date - b.date; }); console.log(items);

Answer 2

您需要使用reduce() 。

 var items = [ {title: 'Hiking', date: new Date('2020-05-10')}, {title: 'Shopping', date: new Date('2020-05-10')},{title: 'Hiking', date: new Date('2020-05-22')}, {title: 'Football', date: new Date('2020-05-22')}, {title: 'Football', date: new Date('2020-05-28')}, {title: 'Hiking', date: new Date('2020-05-28')}, {title: 'Cricket', date: new Date('2020-05-28')}]; var result = items.reduce((acc, {title, date})=>{ dateKey = new Date(date).toISOString().slice(0,10); acc[dateKey] = acc[dateKey] || []; acc[dateKey].push({title}); return acc; },{}); console.log(result);