呈現多個 NodeJs 查詢的問題

Question

我正在嘗試使用 Nodejs 在視圖中呈現幾個查詢，但控制台返回 Promise {pending }。

請幫忙，我不知道我做錯了什么。

router.get('/edit/:id', function (req, res, next) {
const{id} = req.params;
const linksUpdate = db.query('SELECT L.id,L.title,L.url,L.description,U.fullname,U.id FROM links AS L INNER JOIN users AS U ON L.user_id=U.id WHERE L.id = ?'[id], (error, results, fields) => {
if (error) throw error;
const users = db.query("SELECT U.id, U.username, U.password, U.fullname FROM users AS U", (error, resp, 
fields) => { if (error) throw error;
  console.log(linksUpdate);
  console.log(users);
   res.render('links/edit', {linksUpdate: linksUpdate,users: users
     });
        });
    });
});

Answer 1

您需要在db.query()的回調中移動邏輯，例如

router.get('/edit/:id', function(req, res, next) {
   const { id } = req.params;
   db.query('SELECT L.id,L.title,L.url,L.description,U.fullname,U.id FROM links AS L INNER JOIN users AS U ON L.user_id=U.id WHERE L.id = ?' [id], (error, linksUpdate) => {
        if (error) return next(err);
        db.query("SELECT U.id, U.username, U.password, U.fullname FROM users AS U", (error, users) => {
            if (error) return next(err);
            console.log(linksUpdate);
            console.log(users);
            res.render('links/edit', {
                linksUpdate: linksUpdate,
                users: users
            });
        });
    });
});

或等待返回的承諾，而不是使用回調，如此處詳細說明：https://codeburst.io/node-js-mysql-and-async-await-6fb25b01b628