Forge Migrate CodeIgniter 4 外鍵錯誤

Question

使用或遷移Codeigniter生成關系時出現如下代碼或錯誤

遷移產品

public function up()
{

    $this->forge->addField([
        'id'            => [
            'type'           => 'INT',
            'unsigned'       => TRUE,
            'auto_increment' => TRUE
        ],
        'categories_id' => [
            'type'          => 'INT'
        ],
        'product'       => [
            'type'          => 'VARCHAR',
            'constraint'    => '255'
        ]
    ]);
    $this->forge->addKey('id', TRUE);
    $this->forge->createTable('products');
    $this->forge->addForeignKey('categories_id', 'categories', 'id');

}

遷移類別

$this->forge->addField([
        'id'            => [
            'type'           => 'INT',
            'unsigned'       => TRUE,
            'auto_increment' => TRUE
        ],
        'category'      => [
            'type'          => 'VARCHAR',
            'constraint'    => '255'
        ],
        'ordination'    => [
            'type'          => 'INTEGER'
        ],
        'isactive'      => [
            'type'          => 'INTEGER',
            'default'       => 1
        ]
    ]);

    $this->forge->addKey('id', TRUE);
    $this->forge->createTable('categories');

錯誤

類型：CodeIgniter\Database\Exceptions\DatabaseException 消息：未找到字段categories_id 。

Answer 1

這段代碼的問題是在調用之后

$this->forge->createTable('products');

它將重置查詢 object，因此它將丟失對表的引用，並且不會找到您要查找的特定字段。 因此，像這樣更改查詢的順序：

$this->forge->addForeignKey('categories_id', 'categories', 'id');
$this->forge->createTable('products');

Answer 2

感謝您的回答，我已經嘗試過這樣做，但是仍然報錯，正確的事情（后來我設法解決了）是以這種方式生成 categories_id 字段並按照您提到的方式進行調用

'categories_id' => ['type' => 'INT',
                    'unsigned' => TRUE]

$this->forge->addForeignKey('categories_id', 'categories', 'id');
$this->forge->createTable('products');

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