[英]How to parse a string in spirit and use it as return value
我需要解析一個鍵值對,其中鍵本身是一個固定字符串 lke 'cmd' 在示例中。 不幸的是 qi::lit 沒有綜合屬性並且 qi::char_ 解析沒有固定的字符串。 以下代碼無法編譯。 執行后我需要那個 result.name == cmd 。
#include <boost/spirit/include/qi.hpp>
#include <boost/spirit/include/phoenix.hpp>
#include <iomanip>
#include <string>
namespace qi = boost::spirit::qi;
namespace px = boost::phoenix;
struct CommandRuleType
{
std::string name;
int arg;
};
BOOST_FUSION_ADAPT_STRUCT(CommandRuleType, name, arg)
int main() {
qi::rule<std::string::const_iterator, CommandRuleType(), qi::space_type> rule = qi::lit("cmd") >> "=" >> qi::int_;
for (std::string const s : {"cmd = 1" }) {
std::cout << std::quoted(s) << " -> ";
CommandRuleType result;
if (qi::phrase_parse(s.begin(), s.end(), rule, qi::space, result)) {
std::cout << "result: " << result.name << "=" << result.arg << "\n";
} else {
std::cout << "parse failed\n";
}
}
}
qi::lit
不公開屬性。 qi::string
會:
rule = qi::string("cmd") >> "=" >> qi::int_;
#include <boost/spirit/include/phoenix.hpp>
#include <boost/spirit/include/qi.hpp>
#include <iomanip>
#include <string>
namespace qi = boost::spirit::qi;
namespace px = boost::phoenix;
struct CommandRuleType {
std::string name;
int arg;
};
BOOST_FUSION_ADAPT_STRUCT(CommandRuleType, name, arg)
int main() {
qi::rule<std::string::const_iterator, CommandRuleType(), qi::space_type>
rule = qi::string("cmd") >> "=" >> qi::int_;
for (std::string const s : { "cmd = 1" }) {
std::cout << std::quoted(s) << " -> ";
CommandRuleType result;
if (qi::phrase_parse(s.begin(), s.end(), rule, qi::space, result)) {
std::cout << "result: " << result.name << "=" << result.arg << "\n";
} else {
std::cout << "parse failed\n";
}
}
}
印刷
"cmd = 1" -> result: cmd=1
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.