如何打破這個while循環？ [Python]

Question

我正在努力做到這一點，因此當您在 while 循環中輸入數字值時，循環結束，程序也結束。 然而，當我輸入“break”時，我得到一個無效的語法錯誤：（。抱歉編碼不好，這是我第一次。

print('Hello, world!')
print('What is your name?')
myName = input()
print('It is nice to met you, '+ myName)
print('The length of your name is:')
print(len(myName))
print('What is your age?')
myAge=input()
if myAge.isdigit():print('You will be ' + str(int(myAge) + 1) + ' in "one" year')
else: print('that is not a number. Lets try again, what is your age?')
C = 0
while (C<=3):
    myAge2=input()
    C+=1
    if myAge2.isdigit():print('You will be ' + str(int(myAge2) + 1) + ' in "one" year')
    break
    else: print('Try again')

Answer 1

縮進以應用正確的break

 if myAge2.isdigit():
    print('You will be ' + str(int(myAge2) + 1) + ' in "one" year')
    break
 else: 
    print('Try again')

Answer 2

我嘗試簡化代碼：

print('Hello, world!\nWhat is your name')
myName = input()
print('It is nice to met you, {}.\nThe length of your name is: {}'.format(myName, len(myName)))
print('What is your age?')
myAge=input()
if myAge.isdigit():
  print('You will be ' + str(int(myAge) + 1) + ' in "one" year')
else: 
  print('that is not a number. Lets try again, what is your age?')

myAge2=input()
while myAge2.isdigit():
  print('You will be ' + str(int(myAge2) + 1) + ' in "one" year')
  break
else:  
  print('Try again')

Answer 3

代碼縮進有問題，否則一切正常。

print('Hello, world!')
print('What is your name?')
myName = input()
print('It is nice to met you, ' + myName)
print('The length of your name is:')
print(len(myName))
print('What is your age?')
myAge = input()
if myAge.isdigit():
    print('You will be ' + str(int(myAge) + 1) + ' in "one" year')
else:
    print('that is not a number. Lets try again, what is your age?')
C = 0
while (C <= 3):
    myAge2 = input()
    C += 1
    if myAge2.isdigit():
        print('You will be ' + str(int(myAge2) + 1) + ' in "one" year')
        break
    else:
        print('Try again')

Output