命令不能與 subprocess.run 一起使用，但可以與 subprocess.call 一起使用

Question

I am trying to use subprocess.run with a custom argument, that works both directly from windows cmd, and from subprocess.call , but not with subprocess.run , as suggested by Running shell command and capturing the output .

這有效：

    retcode = subprocess.call(build_command_line, shell=True)

這失敗了：

    result = subprocess.run([build_command_line], stdout=subprocess.PIPE, stderr=subprocess.PIPE)

和輸出

The filename, directory name, or volume label syntax is incorrect.
Traceback (most recent call last):
  File "C:\Program Files\Python37\lib\subprocess.py", line 800, in __init__
    restore_signals, start_new_session)
  File "C:\Program Files\Python37\lib\subprocess.py", line 1207, in _execute_child
    startupinfo)
  File "C:\Program Files\JetBrains\PyCharm 2020.1.1\plugins\python\helpers\pydev\_pydev_bundle\pydev_monkey.py", line 551, in new_CreateProcess
    return getattr(_subprocess, original_name)(app_name, patch_arg_str_win(cmd_line), *args)
PermissionError: [WinError 5] Access is denied

即使我與管理員一起運行。

不是說它應該重要，而是為了完整性：

build_command_line是：

'"C:\\Windows\\Microsoft.NET\\Framework\\v4.0.30319\\MSBuild.exe" "C:\\code\\EPMD\\Kodex\\Solutions\\Kodex.All.sln" /t:REBUILD /p:Configuration=RELEASE'

如何讓它與subprocess.run一起使用？

Answer 1

問題是我對subprocess.run的理解

正確調用：

result = subprocess.run(build_command_line, stdout=subprocess.PIPE, stderr=subprocess.PIPE)