我的電梯循環數量做錯了什么？

Question

這是我的專欄 class ，我在第二段中調用了我的電梯數量：

class Column {
constructor(floorsNumber, elevatorsNumber) {
    this.floorsNumber = floorsNumber;
    this.elevatorsNumber = elevatorsNumber;
    this.elevatorsList = [];
    this.directionButtonsList = [];
    
    // Number of elevators
    for (let i = 0; i < elevatorsNumber; i++) {
        this.elevatorsList.push(new Elevator(0, floorsNumber));
}



    for (let i = 0; i < this.floorsNumber; i++) {
        //  floor1 has no DOWN direction button
        if (i === 1) {
            this.directionButtonsList.push(new DirectionButton(i, "up", false));
        } 
        // floor10 has no UP direction button  
        else if (i === 10) {
            this.directionButtonsList.push(new DirectionButton(i, "down", false));
            
        }
         // The rest has both directions
        else {
            this.directionButtonsList.push(new DirectionButton(i, "up", false));
            this.directionButtonsList.push(new DirectionButton(i, "down", false));
        }
    }
}

這就是我如何找到最好的電梯：

// Finding the best  elevator to answer the user's request
findElevator(requestedFloor, direction) {  
    var bestGap = this.floorsNumber;
    var bestElevator = null;

    for (let i = 0; i < this.elevatorsList.length; i++) { 
            // If the elevators and request's direction is moving UP and the requested floor is above the elevator
        if (this.elevatorsList[i].direction === "up" && direction === "up" && requestedFloor > this.elevatorsList[i].currentFloor) {
            bestElevator = this.elevatorsList[i];
        }   // If the elevators and request's direction is moving DOWN and the requested floor is under the elevator
        else if (this.elevatorsList[i].direction === "down" && direction === "down" && requestedFloor < this.elevatorsList[i].currentFloor) {
            bestElevator = this.elevatorsList[i]; 
                 //if elevator and request are descending and the request is below the elevator
        }   // If the elevator is idle
        else if (this.elevatorsList[i].status == "idle") {
            bestElevator = this.elevatorsList[i];
        }
        else {
            for (let i = 0; i < this.elevatorsList.length; i++) {
                // Absolute function is needed otherwise minus numbers would happen and the situation would be misinterpret
                let gap = Math.abs(this.elevatorsList[i].currentFloor - requestedFloor);
                if (gap < bestGap) {
                    bestElevator = this.elevatorsList[i];
                    bestGap = gap;   //Select the smallest gap to find the bestElevator
                }
            }
        }
    }
    console.log("Best elevator is found on floor " + bestElevator.currentFloor);
    return bestElevator; 
}

這是我遇到一個小問題的場景，但我無法將手指放在上面的代碼中我做錯的地方：function Scenario1() {

columntest = new Column(10, 2);

columntest.elevatorsList[0].currentFloor = 2;
columntest.elevatorsList[0].direction = "";
columntest.elevatorsList[0].status = "idle";
columntest.elevatorsList[0].queue = [];

columntest.elevatorsList[1].currentFloor = 5;
columntest.elevatorsList[1].direction = "";
columntest.elevatorsList[1].status = "idle";
columntest.elevatorsList[1].queue = [];

columntest.requestElevator(1, "up");

} 場景 1();`

我的問題是為什么場景不是呼叫我的電梯 [0]，而不是 [1]。 當0明顯比電梯1更近...

Answer 1

據我所知，這是因為這種情況：

 else if (this.elevatorsList[i].status == "idle") {
            bestElevator = this.elevatorsList[i];
        }

對於 for 循環的每次迭代，代碼將按順序運行 if/else 語句。 所以在 i==0 時，電梯沒有向上移動，因此 if 條件被忽略。 電梯沒有向下移動，因此忽略 else if 條件。 電梯空閑，因此運行 else if 條件，並且 bestElevator 設置為該索引，並且不運行 for 循環比較距離。

我認為如果你想在調用空閑電梯之前檢查是否有移動電梯，你必須完全通過陣列來尋找移動電梯，如果沒有找到，那么運行一個循環比較空閑電梯。