使用 Nodejs 訪問返回數據的屬性

Question

我想在 Nodejs 中訪問返回的 Object 的 age 屬性，並且還能夠對其進行過濾。

返回的項目

{"data":"key=IAfpK, age=58, key=WNVdi, age=64, key=jp9zt, age=47, key=0Sr4C, age=68, key=CGEqo, age=76, key=IxKVQ, age=79, key=eD221, age=29, key=XZbHV, age=32, key=k1SN5, age=88, key=4SCsU, age=65, key=q3kG6, age=33, key=MGQpf, age=13, key=Kj6xW, age=14, key=tg2VM, age=30, key=WSnCU, age=24, key=f1Vvz, age=46, key=dOS7A, age=72, key=tDojg, age=82, key=nZyJA, age=48, key=R8JTk, age=29, key=005Ot, age=66, key=HHROm, age=12, key=5yzG8, age=51, key=xMJ5D, age=38, key=TXtVu, age=82, key=Hz38B, age=84, key=WfObU, age=27, key=mmqYB, age=14, key=4Z3Ay, age=62, key=x3B0i, age=55, key=QCiQB, age=72, key=zGtmR, age=66, key=nlIN9, age=8, key=hKalB, age=50, key=Na33O, age=17, key=jMeXm, age=15, key=OO2Mc, age=32, key=hhowx, age=34, key=gLMJf, age=60, key=PblX6, age=66, key=8Vm5W, age=22, key=oZKd6, age=88, key=RXNfQ, age=
{"data":"key=IAfpK, age=58, key=WNVdi, age=64, key=jp9zt, age=47, key=0Sr4C, age=68, key=CGEqo, age=76, key=IxKVQ, age=79, key=eD221, age=29, key=XZbHV, age=32, key=k1SN5, age=88 ...

我的代碼

const https = require('https');

https.get('https://coderbyte.com/api/challenges/json/age-counting', (resp) => {
  let {statusCode} = resp
  let contentType = resp.headers['content-type']
  resp.setEncoding('utf-8')
  let data = '';

  // parse json data here...
  resp.on('data', (d) => {
    data += d
    console.log(data)
  })
  resp.on("error", (e) => {
    console.log("error", e)
  })

  //console.log(resp);

});

請問有人可以幫忙嗎？？

Answer 1

感謝大家，我現在可以使用此代碼訪問它。

但我想將日志折疊到一個 integer，有人能指出來嗎？

const https = require('https');

https.get('https://coderbyte.com/api/challenges/json/age-counting', (resp) => {
  let {statusCode} = resp
  let contentType = resp.headers['content-type']
  resp.setEncoding('utf-8')
  let data = '';

  // parse json data here...
  resp.on('data', (d) => {
    data += [d]
  })

    resp.on('end', () => {
    let parsedData = data.split(",")
    .filter(data =>!data.indexOf(" age="))
    .map(data => data.replace(" age=",""))
    .map(data => parseInt(data))
    .filter(data => {
     return (data >= 50);
    }).length
    console.log(parsedData);
  })
  resp.on("error", (e) => {
    console.log("error", e)
  })

  //console.log(resp);

});

Answer 2

如果要訪問年齡屬性，則必須驗證數據是否為 object。

因為如果數據的類型是字符串， data.age沒有定義。

你應該使用

let dataParsed = JSON.parse(data)

最后，定義dataParsed.age 。

如果您有意外錯誤，請使用：

JSON.parse(JSON.stringify(data))

Answer 3

請檢查您是否正在尋找這樣的東西。

 const response = {"data":"key=IAfpK, age=58, key=WNVdi, age=64, key=jp9zt, age=47, key=0Sr4C, age=68, key=CGEqo, age=76, key=IxKVQ, age=79, key=eD221, age=29, key=XZbHV, age=32"} console.log(response.data.split(",").filter(data =>.data.indexOf(" age=")).map(data => data,replace(" age=";"")));

這將產生以下結果：

 [
"58",
"64",
"47",
"68",
"76",
"79",
"29",
"32"
]

Answer 4

const https = require("https");
var fs = require("fs");
const crypto = require("crypto");

https.get("https://coderbyte.com/api/challenges/json/age-counting", (resp) => {
  let { statusCode } = resp;
  let contentType = resp.headers["content-type"];
  resp.setEncoding("utf-8");
  let data = "";

  // parse json data here...
  resp.on("data", (d) => {
    data += [d];
  });
  let array = [];
  sortedArray = [];

  resp.on("end", () => {
    newarray = JSON.parse(data).data.split(",");
    array = [];
    newarray.forEach((val, index) => {
      if (!val.includes(" age=")) {
        keyValue = val.replace(" key=", "");
        keyValue = keyValue.replace("key=", "");
        let age = newarray[index + 1].replace(" age=", "");
        if (age > 32) {
          sortedArray.push([keyValue]);
          array.push({
            [keyValue]: age,
          });
        }
      }
    });
    const writeStream = fs.createWriteStream("output.txt");
    const pathName = writeStream.path;
    sortedArray.forEach((value) => writeStream.write(`${value}\n`));

    // the finish event is emitted when all data has been flushed from the stream
    writeStream.on("finish", () => {
      const fileBuffer = fs.readFileSync("output.txt");
      const hashSum = crypto.createHash("sha256");
      hashSum.update(fileBuffer);
      const hex = hashSum.digest("hex");
      console.log(hex);
    });

    // handle the errors on the write process
    writeStream.on("error", (err) => {
      console.error(`There is an error writing the file ${pathName} => ${err}`);
    });

    // close the stream
    writeStream.end();
  });

  //console.log(resp);
});

Answer 5

如果您只想獲取最后一個 integer 即 no of age 屬性，那么您必須將代碼移動到“結束”事件。

const https = require('https');

  https.get('https://coderbyte.com/api/challenges/json/age-counting', (resp) => {
   let {statusCode} = resp
   let contentType = resp.headers['content-type']
   resp.setEncoding('utf-8')
   let data = '';

  // parse json data here...
  resp.on('data', (d) => {
    data += [d]
  })

  resp.on('end', () => {
    let parsedData = data.split(",")
    .filter(data =>!data.indexOf(" age="))
    .map(data => data.replace(" age=",""))
    .map(data => parseInt(data))
    .filter(data => {
     return (data >= 50);
    }).length
    console.log(parsedData);
  })
  resp.on("error", (e) => {
    console.log("error", e)
  })

  //console.log(resp);

});

Answer 6

這可能是您的解決方案：

const https = require('https');

https.get('https://coderbyte.com/api/challenges/json/age-counting', (resp) => {
  let data = ''
    resp.on('data', (chunk) => {
      data+=chunk;
    });
    resp.on('end', () => {
      let jsonData = JSON.parse(data.toString());
      let actualData = jsonData.data;
      let arr1 = actualData.split(", ");
      let totalCount = 0;
      for(let i = 0; i < arr1.length; i++){
        let item = arr1[i];
        if(item.indexOf('age=') !== -1){
          let age = item.split('=');
          if(parseInt(age[1]) >= 50) {
            totalCount++;
          }
        }
      }
      console.log(totalCount);
    })
});

資料來源： https://amudalvi.blogspot.com/p/coderbyte-node-js-age-counting.html

Answer 7

在 Swift 語言中我試過了。 我正在解碼數據，然后轉換為 json object。

struct DataObject: Decodable {
let data: String
}


let jsonData = JSON.data(using: .utf8)!
let dataObject: DataObject = try! JSONDecoder().decode(DataObject.self, from: jsonData)
 // print(dataObject.data)
var count = 0
for item in dataObject.data.split(separator: ","){
let age = item.split(separator: "=")
let stringAge =  age[0]

if(stringAge == " age"){
    //  print("String agae", stringAge)
     let ageInt = age[1]
    //  print("String agae Int ", ageInt)
     if Int(String(ageInt))! >= 50){
        count = count + 1 
     }
    // print("age and key",age)
}
}

Answer 8

這是我對這個的看法

const https = require('https');

https.get('https://coderbyte.com/api/challenges/json/age-counting', (resp) => {
  let data = '';

  resp.on('data', (chunk) => {
    data = data += chunk
  })

  resp.on('end',  () => {
    let parsedData = JSON.parse(data.toString()).data
    let arrayData = parsedData.split(", ")

    let ageArray = [];
    for (i = 0; i < arrayData.length; i++) {
      if (i%2 === 1) {
        ageArray.push(Math.floor(arrayData[i].slice(4)))
      }
    }

    let filteredArray = ageArray.filter((item) => {
      return item >= 50
    })

    console.log(filteredArray.length)
  })
});

您可以操作您的 output 陣列，直到您只獲得您真正需要的唯一部分，即數字。 然后您可以輕松地按值過濾該數組並返回它的長度。

Answer 9

const response =  {"data":"key=IAfpK, age=58, key=WNVdi, age=64, key=jp9zt, age=47, key=0Sr4C, age=68, key=CGEqo, age=76, key=IxKVQ, age=79, key=eD221, age=29, key=XZbHV, age=32"}
const count = response.data.split(",").map(value=>value.split("=")).filter(value=> value[0]===" age").reduce((cumulative,current)=>{if(Number(current[1])>=50){ return cumulative+1}else{return cumulative}},0);
console.log(count)