您如何使用 Date.new 將每個月的記錄范圍限制為幾周？ Ruby 上軌 6

Question

為了澄清，我正在構建一個搜索，它采用三個參數，即月/年/周數。 我需要知道如何根據傳遞的周數返回記錄。 例如，最有可能有 5 周。 當我 select 所有三個參數時，我應該得到 7 天或更短的記錄。 就目前而言，我已成功按月/年檢索記錄，但現在我將周數作為參數引入。 你如何將周數傳遞給 date.new object？

索引.html.erb

  <%= form_tag amb_chart_records_path, :method => :get, :class => "ui form" %>
    <div class="three fields">
     <div class="field">
      <%= select_month(@month.present? @month : nil, {:include_blank => "Select Month"...%>
    </div>
    <div class="field">
        <%= select_year(@year.present? ? @year : Date.today, {:include_blank => "Select Year"..%>
    </div>
    <div class="field">
      <%= select_tag :week, options_for_select([["Week 1", 1], ["Week 2", 2], ["Week 3", 3], ["Week 4", 4], ["Week 5", 5]], params[:week]), class: 'ui dropdown' %>
    </div>    
    </div>
  <div class="field text-center">
    <%= submit_tag("Search", :id => "button", :class => "ui button basic green" %>
  </div>
    <% end %>

amb_chart_records_controller.rb

def index
  if params[:commit] == "Previous" || params[:commit] == "Next"
    now = Date.new(params[:current_year].to_i, params[:current_month].to_i)
    if params[:commit] == "Previous"
      target_date = now - 1.month
    else
      target_date = now + 1.month
    end
  elsif params.has_key?(:select)
    target_date = Date.new(params[:select][:year].to_i, params[:select][:month].to_i, 1)
    week_numb = params[:select][:week].to_i
  else
    target_date = Date.new(Date.today.year, Date.today.month, 1)
    week_numb = 1
  end
  @year = target_date.year.to_i
  @month = target_date.month.to_i
  @week_numb = target_date.cweek.to_i
  @facilities = Facility.where(is_ambulatory_chart_enabled: true)
  @ambulatory_chart_records = @facilities.includes(:amb_chart_records).order(record_date: :desc).where(:record_date => target_date..target_date + 1.month)
end

def week(year, month, week_number)
  Date.new(year, month, 7 * week_number - 6)
end

Answer 1

要在 Ruby 中獲得一周的開始，請使用Date#commercial方法：

irb(main):019:0> Date.commercial(2020, 25, 1)
=> Mon, 15 Jun 2020

這假設周從星期一開始。 如果您需要從星期日開始的 ISO 周，只需使用#change將日期更改為一天：

irb(main):020:0> Date.commercial(2020, 25, 1).change(day: -1)
=> Tue, 30 Jun 2020

如果您想根據周數進行查詢，一種方法是在開始日期和結束日期之間傳遞一個范圍：

w_start = Date.commercial(year, week_number, 1)
w_end = Date.commercial(year, week_number, 7)
Model.where(some_column: w_start..w_end)

作為一個較少多語言的解決方案，您還可以使用數據庫中的日期函數從日期列中提取周數：

# Postgres
User.where('EXTRACT(week from created_at)::int = ?', 26)
    .where('EXTRACT(year from created_at)::int = ?', 2020)

# MySQL
User.where('WEEK(created_at) = ?', 26)
    .where('YEAR(created_at) = ?', 2020)

如果您使用基於周的分組或聚合，這將更加有用。