如何從存儲在元組列表列表中的兩個元素元組中創建兩個列表

Question

我有一個列表，其中包含許多列表，其中有 4 個元組。

my_list = [[(12, 1), (10, 3), (4, 0), (2, 0)],
           [(110, 1), (34, 2), (12, 1), (55, 3)]]

我希望它們在兩個單獨的列表中，例如：

my_list2 = [12,10,4,2,110,34,12,55]
my_list3 = [1,3,0,0,1,2,1,3]

我的嘗試是為此使用map function。

my_list2 , my_list3 = map(list, zip(*my_list))

但這給了我一個錯誤：

ValueError: too many values to unpack (expected 2)

Answer 1

您的方法非常接近，但您需要先展平：

from itertools import chain

my_list = [[(12, 1), (10, 3), (4, 0), (2, 0)], [(110, 1), (34, 2), (12, 1), (55, 3)]]

my_list2 , my_list3 = map(list,zip(*chain.from_iterable(my_list)))

my_list2
# [12, 10, 4, 2, 110, 34, 12, 55]

my_list3
# [1, 3, 0, 0, 1, 2, 1, 3]

Answer 2

一種不同的，簡單的方法：

my_list = [[(12, 1), (10, 3), (4, 0), (2, 0)], [(110, 1), (34, 2), (12, 1), (55, 3)]]

first = []
second = []

for inner in my_list:
    for each in inner:
        first.append(each[0])
        second.append(each[1])

print(first)  # [12, 10, 4, 2, 110, 34, 12, 55]
print(second)  # [1, 3, 0, 0, 1, 2, 1, 3]

Answer 3

您可以使用列表理解 (5.1.3) 。

第一個元組數：

my_list2 = [tuple[0] for inner in my_list for tuple in inner]

第二個元組數：

my_list3 = [tuple[1] for inner in my_list for tuple in inner]

Answer 4

試試看：

my_list = [[(12, 1), (10, 3), (4, 0), (2, 0)], [(110, 1), (34, 2), (12, 1), (55, 3)]]

my_list2, my_list3 = map(list, zip(*[j for i in my_list for j in i]))
print(my_list2)
# [12, 10, 4, 2, 110, 34, 12, 55]
print(my_list3)
# [1, 3, 0, 0, 1, 2, 1, 3]

Answer 5

這個怎么樣？

my_list = [[(12, 1), (10, 3), (4, 0), (2, 0)], [(110, 1), (34, 2), (12, 1), (55, 3)]]

flatten = lambda l: [item for my_list in l for item in my_list]

list1, list2 = zip(*flatten(my_list))

Answer 6

這是一種方法：

my_list = [[(12, 1), (10, 3), (4, 0), (2, 0)], [(110, 1), (34, 2), (12, 1), (55, 3)]]

my_list2 = [a for b in [[t[0] for t in my_list[i]] for i,n in enumerate(my_list)] for a in b]
my_list3 = [a for b in [[t[1] for t in my_list[i]] for i,n in enumerate(my_list)] for a in b]

print(my_list2)
print(my_list3)

Output：

[12, 10, 4, 2, 110, 34, 12, 55]
[1, 3, 0, 0, 1, 2, 1, 3]

Answer 7

一個極簡的解決方案怎么樣：

my_list = [[(12, 1), (10, 3), (4, 0), (2, 0)], [(110, 1), (34, 2), (12, 1), (55, 3)]]

my_list2, my_list3 = zip(*sum(my_list, []))

print(my_list2)
print(my_list3)

OUTPUT

> python3 test.py
(12, 10, 4, 2, 110, 34, 12, 55)
(1, 3, 0, 0, 1, 2, 1, 3)
>