[英]Is it possible to use the DeviceCode authentication Flow with Azure Java SDK?
我使用 azure msal4j
庫成功生成了IAuthenticationResult
- 我看到了一個設備代碼,當將該代碼輸入瀏覽器時,它顯示了正確的范圍/權限,現在我想獲取此身份驗證結果並通過它進入 Azure-SDK 身份驗證,類似於:
val result = DeviceCodeFlow.acquireTokenDeviceCode()
val a: Azure = Azure.configure()
.withLogLevel(LogLevel.BODY_AND_HEADERS)
.authenticate(AzureCliCredentials.create(result))
.withDefaultSubscription()
有誰知道在哪里看/或任何這樣做的樣本?
如果要使用msal4j
庫獲取訪問令牌,則使用令牌管理 Azure 資源與 Azure 管理 SDK,請參考以下代碼
public class App {
public static void main(String[] args) throws Exception {
String subscriptionId = ""; // the subscription id
String domain="";// Azure AD tenant domain
DeviceCodeTokenCredentials tokencred = new DeviceCodeTokenCredentials(AzureEnvironment.AZURE,domain);
Azure azure =Azure.configure()
.withLogLevel(LogLevel.BASIC)
.authenticate(tokencred)
.withSubscription(subscriptionId);
for(AppServicePlan plan : azure.appServices().appServicePlans().list()) {
System.out.println(plan.name());
}
}
}
// define a class to extend AzureTokenCredentials
class DeviceCodeTokenCredentials extends AzureTokenCredentials{
public DeviceCodeTokenCredentials(AzureEnvironment environment, String domain) {
super(environment, domain);
}
@Override
public String getToken(String resource) throws IOException {
// use msal4j to get access token
String clientId="d8aa570a-68b3-4283-adbe-a1ad3c1dfd8d";// you Azure AD application app id
String AUTHORITY = "https://login.microsoftonline.com/common/";
Set<String> SCOPE = Collections.singleton("https://management.azure.com/user_impersonation");
PublicClientApplication pca = PublicClientApplication.builder(clientId)
.authority(AUTHORITY)
.build();
Consumer<DeviceCode> deviceCodeConsumer = (DeviceCode deviceCode) ->
System.out.println(deviceCode.message());
DeviceCodeFlowParameters parameters =
DeviceCodeFlowParameters
.builder(SCOPE, deviceCodeConsumer)
.build();
IAuthenticationResult result = pca.acquireToken(parameters).join();
return result.accessToken();
}
}
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.