通過公共鍵/索引合並數組項和 object 值

Question

我有一個像這樣的 arrays 數組：

let a = [ 
   ['A', 'B'], // 1 in the object
   ['C'], // 2 in the object
];

我有一個像這樣的對象的 object：

let b = {
    5:{
         1: "i was send to earth. i was send to her.",
         2: "to mars",
         3: { reference: "to moon.", expectSt: "to mars. i love it." },
    },
};

如您所見，object 中有兩種模式。 像 1 和 2 的模式和像 3 的模式。

我只想將 1 中的句子添加到let a內的第一個數組中，並將 2 中的句子添加到let a a 內的第二個數組中，依此類推......

如果模式像 3 那么我只想添加expectSt句子並忽略reference

結果應該是這樣的：

let a = [ 
       ['A', 'B', 'i was send to earth', 'i was send to her'], // 1 in the object
       ['C', 'to mars'], // 2 in the object
       ['to mars', 'i love it'], // there is a 3 i the object so we added this
];

我已經嘗試了很多，但我認為我需要幫助解決這個問題。

Answer 1

這么簡單的事情對你有用嗎？

 let a = [['A','B'],['C'],], b = {5:{1:"i was send to earth. i was send to her.",2:"to mars",3:{reference:"to moon.",expectSt:"to mars. i love it."},},} Object.values(b[5]).forEach((value,key) => a[key] = [...(a[key]||[]), ...(value.expectSt || value).toLowerCase().replace(/\.$/,'').split('. ') ] ) console.log(a)

 .as-console-wrapper{min-height:100%;}

Answer 2

let a = [ 
  ['A', 'B'], // 1 in the object
  ['C'], // 2 in the object
];

let b = {
  5:{
       1: "i was send to earth. i was send to her.",
       2: "to mars",
       3: { reference: "to moon.", expectSt: "to mars. i love it." },
  },
};

Object.values(b).forEach(element => {
  Object.keys(element).forEach(e => {
    console.log(element[e]);
    if(e === '1') a[0].push(...element[e].split('.').filter(a => a !== '').map(a => a.trim()));
    else if(e === '2') a[1].push(...element[e].split('.').filter(a => a !== '').map(a => a.trim()));
    else if(e === '3') {
      if(a.length < 3) a.push([]);
      a[2].push(...element[e].expectSt.split('.').filter(a => a !== '').map(a => a.trim()))
    } 
  })
});

console.log(a);