JSHELL JDK API：拋出異常時拒絕片段

Question

我正在為學生創建一個簡單的 jshell 來技術 java，我想使用 JUNIT 的斷言，但是當拋出異常時，片段不被拒絕，我看到它可能需要一個自定義執行引擎，但它太多了。

這是我的代碼，它將在 IDE 上運行 REPL，但它不會拒絕throw new Exception("Exception message");

package simple.repl;

import java.io.*;
import java.util.List;
import jdk.jshell.*;
import jdk.jshell.Snippet.Status;

public class Main {

    public static void main(String[] args) throws IOException {

        try (JShell js = JShell.builder().in(System.in).out(System.out).err(System.out).build()) {

            for (final String str : System.getProperty("java.class.path").split(File.pathSeparator)) {
                js.addToClasspath(str);
            }

            do {
                //input System.out.println("hello");
                //int as = 1;
                //throw new Exception("Exception message");
                System.out.print("Enter some Java code: ");
                BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
                String input= reader.readLine();

                if (input == null) {
                    break;
                }
                List<SnippetEvent> events = js.eval(input);
                for (SnippetEvent e : events) {
                    StringBuilder sb = new StringBuilder();
                    if (e.causeSnippet() == null) {
                        //  We have a snippet creation event
                        switch (e.status()) {
                            case VALID:
                                sb.append("Successful ");
                                break;
                            case RECOVERABLE_DEFINED:
                                sb.append("With unresolved references ");
                                break;
                            case RECOVERABLE_NOT_DEFINED:
                                sb.append("Possibly reparable, failed  ");
                                break;
                            case REJECTED:
                                sb.append("Failed ");
                                break;
                        }
                        if (e.previousStatus() == Status.NONEXISTENT) {
                            sb.append("addition");
                        } else {
                            sb.append("modification");
                        }
                        sb.append(" of ");
                        sb.append(e.snippet().source());
                        System.out.println(sb);
                        if (e.value() != null) {
                            System.out.printf("Value is: %s\n", e.value());
                        }
                        System.out.flush();
                    }
                }
            } while (true);
        }
        System.out.println("\nGoodbye");
    }
}

Answer 1

更新：

如果 java 代碼語法正確，則片段將被標記為 Status.VALID，即使在運行時出現異常/錯誤，檢查片段異常使用snippetEvent.exception() != null

if (snippetEvent.exception() != null) {
System.out.println("Exception : " + snippetEvent.exception().getMessage());
}