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[英]How to get last object from array of object based on condition in angular 8
[英]how to get array of object based on condition in javascript
我有兩個數組對象arr1
和arr2
,
arr1
屬性qty
應小於相同name
的庫存 arr1 和數量 arr2 的總和。
如何根據 javascript 中的屬性和同名比較返回數組 object
function getArray(arr1,arr2)
{
return arr1.filter(i=> arr2.map(e=>i. qty < (e.quantity+i.stock)))
}
var arr1=[
{id:1, name: "sample1", qty:2, stock: 0},
{id:2, name: "sample2", qty:3, stock: 2},
{id:3, name: "sample2", qty:4, stock: 1}
]
var arr2=[
{idx:1, name:"sample1", quantity:1},
{idx:2, name:"sample2", quantity:2},
{idx:3, name:"sample3", quantity:1}
]
預計 Output,
[{id:1, name: "sample1", qty:2, stock: 0},
{id:3, name: "sample2", qty:4, stock: 1}]
嘗試這個:
arr1.filter(item1=>item1.stock<(arr2.filter(item2=>item2.name==item1.name))[0].quantity)
只要 array2 具有唯一的名稱,它就可以工作。
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