[英]SQL average Percentage by group
我有一些示例記錄的 table1(將有超過 100 條記錄)
lastname courtesy
Lane 3
Lane 4
Lane 5
Lane 12
Santana 4
Santana 5
我的查詢是按姓氏獲取 ave 百分比組,但沒有按姓氏分組
你可以看到萊恩和桑塔納仍然沒有分組。
請更正查詢。 謝謝你。
SELECT
lastname,
courtesy,
percentage = AVG(courtesy) * 100 / SUM(AVG(courtesy)) OVER (PARTITION BY lastname)
FROM echo
GROUP BY
lastname, courtesy
結果
lastname courtesy percentage
Lane 3 12
Lane 4 16
Lane 5 20
Lane 12 50
Santana 4 44
Santana 5 55
結果看起來像這樣
lastname percentage
Lane 16 (4/24)
Satana 22 (2/9)
count (lastname) / sum (courtesy) group by lastname
我認為這是您想要的邏輯:
SELECT lastname,
SUM(SUM(courtesy)) OVER (ORDER BY lastname),
COUNT(*) * 1.0 / SUM(courtesy)
FROM echo
GROUP BY lastname;
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