[英]How to rewrite my append line in Python 3 code?
我的代碼
token = open('out.txt','r')
linestoken=token.readlines()
tokens_column_number = 1
r=[]
for x in linestoken:
r.append(x.split()[tokens_column_number])
token.close()
print (r)
Output
'"tick2/tick_calculated_2_2020-05-27T11-59-06.json.gz",'
所需 output
"tick2/tick_calculated_2_2020-05-27T11-59-06.json.gz"
如何擺脫''
和,
?
很高興看到您的輸入數據。 我創建了一個與您的相似的輸入文件(我希望如此)。
我的測試文件內容:
example1 "tick2/tick_calculated_2_2020-05-27T11-59-06.json.gz", aaaa
example2 "tick2/tick_calculated_2_2020-05-27T11-59-07.json.gz", bbbb
您應該替換"
, ',' 字符。
您可以通過replace
( https://docs.python.org/3/library/stdtypes.html#str.replace )來做到這一點:
r.append(x.split()[tokens_column_number].replace('"', "").replace(",", ""))
您可以使用strip
( https://docs.python.org/2/library/string.html#string.strip ):
r.append(x.split()[tokens_column_number].strip('",'))
您可以使用re.sub
( https://docs.python.org/3/library/re.html#re.sub ):
import re
...
...
for x in linestoken:
x = re.sub('[",]', "", x.split()[tokens_column_number])
r.append(x)
...
...
Output 在這兩種情況下:
>>> python3 test.py
['tick2/tick_calculated_2_2020-05-27T11-59-06.json.gz', 'tick2/tick_calculated_2_2020-05-27T11-59-07.json.gz']
As you can see above the output ( r
) is a list
type but if you want to get the result as a string, you should use the join
( https://docs.python.org/3/library/stdtypes.html# str.join )。
Output 與print(",".join(r))
:
>>> python3 test.py
tick2/tick_calculated_2_2020-05-27T11-59-06.json.gz,tick2/tick_calculated_2_2020-05-27T11-59-07.json.gz
Output 與print("\n".join(r))
:
>>> python3 test.py
tick2/tick_calculated_2_2020-05-27T11-59-06.json.gz
tick2/tick_calculated_2_2020-05-27T11-59-07.json.gz
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