curl 請求 - 更改為 RestTemplate - 無正文錯誤

Question

我有一個 curl 命令，它工作正常，但是當我在 RestTemplate 中嘗試它時，我遇到了錯誤。

Curl：

curl -X POST "https://api.example.com/v1/tokens/accessToken" -H  "accept: application/json" -H  "Content-Type: application/json" -d "{  \"refresh_token\": \"eyJhbGciOiJSUzUxMiIsInR5cCI6IkpXVCIsIng1dCI6IndKZlQ2NHpqemQxWk4yS1duX3FYSmpvOHByMCIsImtpZCI6Im9yYWtleSJ9.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.UjJKgHkCypoyIsK7-24vUdX4jT2vkODW56tfwNuAnFqvaS712ZdDAQFiu5wjS9sCajAx0LDoJXQoq5ThVliY71FU9cvwS80SRpXzEIX_TcnnOfNXyZBzTyCqKDPjin0ajZ9Jvc_LNbMMD15i0tN3U6IQHmahm8yikGL7lBtvT30\"}"

Spring Rest 模板

    restTemplate = new RestTemplate();
    HttpHeaders headers = new HttpHeaders();
    headers.setContentType(MediaType.APPLICATION_JSON);
    headers.setAccept(Collections.singletonList(MediaType.APPLICATION_JSON));

    Map<String, Object> map = new HashMap<>();
    map.put("body", "{\"refresh_token\": \"eyJhbGciOiJSUzUxMiIsInR5cCI6IkpXVCIsIng1dCI6IndKZlQ2NHpqemQxWk4yS1duX3FYSmpvOHByMCIsImtpZCI6Im9yYWtleSJ9.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.UCkScWFn8d3pupwAxilT8T-m6Rf8fgZ8ge9OZvWZbZ-4eCVCPyHeI8A1a2QV0_iZhjwHaITNTzCZ4Eydfkm-mZuCa-PLY63HJhWLzTGlbaYsWRVtHaLF58F6spZ106T6T3ZDvQVIsiQ9845ruG_1ib0vKV_57X_CcVB4XZktYvA\"}");

    HttpEntity<Map<String, Object>> entity = new HttpEntity<>(map, headers);

    String urlString = "https://api.example.com/v1/tokens/accessToken";
    String response = restTemplate.postForObject(urlString, entity, String.class);

例外：

Caused by: org.springframework.web.client.HttpServerErrorException$InternalServerError: 500 Internal Server Error: [{"error":"Request Failed"}]

那么如何正確地將以上 curl 轉換為 RestTemplate 以避免服務器和無正文錯誤。 Curl 命令運行良好。

Answer 1

嘗試這個

    restTemplate = new RestTemplate();
    HttpHeaders headers = new HttpHeaders();
    headers.setContentType(MediaType.APPLICATION_JSON);
    headers.setAccept(singletonList(MediaType.APPLICATION_JSON));
    HttpEntity<String> entity = 
             new HttpEntity<>("{\"refresh_token\": \"eyJhb...\"}", headers);

Answer 2

正如您正確注意到的那樣，您應該使用：

map.put("refresh_token", "eyJhbGci...". 

但是你有 401 只是因為你傳遞了另一個令牌（檢查差異 cURL 與 java 代碼版本）

Answer 3

如果令牌具有類型，例如 Bearer，請檢查您的令牌，您必須這樣寫：

"Authorization": "Bearer rrdedzfdgf........."

並確保 Bearer 和 token 之間只有一個空格