[英]How to optimize this simulation in Java?
我正在嘗試在 Java 中進行多線程模擬,並且我已經設法使用隊列來完成,但是執行時間很長,關於如何優化它的任何想法? 使用遞歸可以節省時間嗎?
輸入必須是這樣的:
這是代碼:
import java.io.*;
import java.util.HashMap;
import java.util.HashSet;
import java.util.PriorityQueue;
import java.util.Set;
import java.util.StringTokenizer;
public class JobQueue {
private int numWorkers;
private int[] jobs;
private int[] assignedWorker;
private long[] startTime;
private FastScanner in;
private PrintWriter out;
public static void main(String[] args) throws IOException {
new JobQueue().solve();
}
private void readData() throws IOException {
numWorkers = in.nextInt();
int m = in.nextInt();
jobs = new int[m];
for (int i = 0; i < m; ++i) {
jobs[i] = in.nextInt();
}
}
private void writeResponse() {
for (int i = 0; i < jobs.length; ++i) {
out.println(assignedWorker[i] + " " + startTime[i]);
}
}
private void assignJobs() {
// TODO: replace this code with a faster algorithm.
assignedWorker = new int[jobs.length];
startTime = new long[jobs.length];
PriorityQueue<Integer> nextTimesQueue = new PriorityQueue<Integer>();
HashMap<Integer, Set<Integer>> workersReadyAtTimeT = new HashMap<Integer,Set<Integer>>();
long[] nextFreeTime = new long[numWorkers];
int duration = 0;
int bestWorker = 0;
for (int i = 0; i < jobs.length; i++) {
duration = jobs[i];
if(i<numWorkers) {
bestWorker = i;
nextTimesQueue.add(duration);
addToSet(workersReadyAtTimeT, duration, i,0);
}else {
int currentTime = nextTimesQueue.poll();
Set<Integer> workersReady = workersReadyAtTimeT.get(currentTime);
if (workersReady.size()>1) {
bestWorker = workersReady.iterator().next();
workersReady.remove(bestWorker);
workersReadyAtTimeT.remove(currentTime);
workersReadyAtTimeT.put(currentTime,workersReady);
nextTimesQueue.add(currentTime);
} else {
bestWorker = workersReady.iterator().next();
workersReadyAtTimeT.remove(currentTime);
nextTimesQueue.add(currentTime+duration);
addToSet(workersReadyAtTimeT, duration, bestWorker, currentTime);
}
}
assignedWorker[i] = bestWorker;
startTime[i] = nextFreeTime[bestWorker];
nextFreeTime[bestWorker] += duration;
}
}
private void addToSet(HashMap<Integer, Set<Integer>> workersReadyAtTimeT, int duration, int worker, int current) {
if(workersReadyAtTimeT.get(current+duration)==null) {
HashSet<Integer> s = new HashSet<Integer>();
s.add(worker);
workersReadyAtTimeT.put(current+duration, s);
}else {
Set<Integer> s = workersReadyAtTimeT.get(current+duration);
s.add(worker);
workersReadyAtTimeT.put(current+duration,s);
}
}
public void solve() throws IOException {
in = new FastScanner();
out = new PrintWriter(new BufferedOutputStream(System.out));
readData();
assignJobs();
writeResponse();
out.close();
}
static class FastScanner {
private BufferedReader reader;
private StringTokenizer tokenizer;
public FastScanner() {
reader = new BufferedReader(new InputStreamReader(System.in));
tokenizer = null;
}
public String next() throws IOException {
while (tokenizer == null || !tokenizer.hasMoreTokens()) {
tokenizer = new StringTokenizer(reader.readLine());
}
return tokenizer.nextToken();
}
public int nextInt() throws IOException {
return Integer.parseInt(next());
}
}
}
在我看來,您的jobsList
object 是完全多余的,它包含的所有內容也都在jobs
數組中,當您獲取前面的元素時,您會在jobs[i]
獲得項目。 為了加快一點速度,您可以將 int 的構造函數從循環中取出,並為它們分配新的數字。 另一個優化是在第一個numWorkers
作業期間不進行搜索,因為您知道在您耗盡您的池之前您仍然有空閑的工人。 一旦你找到了一名優秀的工人,你就不必繼續尋找,這樣你就可以continue
退出你的 for 循環。
public class JobQueue {
private int numWorkers;
private int[] jobs;
private int[] assignedWorker;
private long[] startTime;
private void readData() throws IOException {
numWorkers = in.nextInt();
int m = in.nextInt();
jobs = new int[m];
for (int i = 0; i < m; ++i) {
jobs[i] = in.nextInt();
}
}
private void assignJobs() {
assignedWorker = new int[jobs.length];
startTime = new long[jobs.length];
long[] nextFreeTime = new long[numWorkers];
int duration = 0;
int bestWorker = 0;
for (int i = 0; i < jobs.length; i++) {
duration = jobs[i];
bestWorker = 0;
if (i< numWorkers){
bestWorker= i;
} else{
for (int j = 0; j < numWorkers; ++j) {
if (nextFreeTime[j] < nextFreeTime[bestWorker])
bestWorker = j;
continue;
}
}
assignedWorker[i] = bestWorker;
startTime[i] = nextFreeTime[bestWorker];
nextFreeTime[bestWorker] += duration;
}
}
但是,您的解決方案和略微縮減的解決方案都需要 2 毫秒才能運行。 我還查看了使用 HashMap 來維護 NextWorker 標記,但在某些時候你趕上了它並最終每次都在尋找下一個並且不會贏得太多。
你可以嘗試有一個有序的列表/隊列,但是你有昂貴的插入而不是昂貴的搜索,你必須跟蹤時間片。 但是這樣的版本可能如下所示:
private void assignJobs() {
assignedWorker = new int[jobs.length];
startTime = new long[jobs.length];
PriorityQueue<Integer> nextTimesQueue = new PriorityQueue<Integer>();
HashMap<Integer, Set<Integer>> workersReadyAtTimeT = new HashMap<Integer,Set<Integer>>();
long[] nextFreeTime = new long[numWorkers];
int duration = 0;
int bestWorker = 0;
for (int i = 0; i < jobs.length; i++) {
duration = jobs[i];
if(i<numWorkers) {
bestWorker = i;
nextTimesQueue.add(duration);
addToSet(workersReadyAtTimeT, duration, i,0);
}else {
int currentTime = nextTimesQueue.poll();
Set<Integer> workersReady = workersReadyAtTimeT.get(currentTime);
if (workersReady.size()>1) {
bestWorker = workersReady.iterator().next();
workersReady.remove(bestWorker);
workersReadyAtTimeT.remove(currentTime);
workersReadyAtTimeT.put(currentTime,workersReady);
nextTimesQueue.add(currentTime);
} else {
bestWorker = workersReady.iterator().next();
workersReadyAtTimeT.remove(currentTime);
nextTimesQueue.add(currentTime+duration);
addToSet(workersReadyAtTimeT, duration, bestWorker, currentTime);
}
}
assignedWorker[i] = bestWorker;
startTime[i] = nextFreeTime[bestWorker];
nextFreeTime[bestWorker] += duration;
}
}
private void addToSet(HashMap<Integer, Set<Integer>> workersReadyAtTimeT, int duration, int worker, int current) {
if(workersReadyAtTimeT.get(current+duration)==null) {
HashSet<Integer> s = new HashSet<Integer>();
s.add(worker);
workersReadyAtTimeT.put(current+duration, s);
}else {
Set<Integer> s = workersReadyAtTimeT.get(current+duration);
s.add(worker);
workersReadyAtTimeT.put(current+duration,s);
}
}
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