將一個字典的值與另一字典的鍵匹配（Python）

Question

晚上所有，

希望你一切都好。

我的目標我試圖將一個字典的值與另一個字典的鍵匹配。

dict1有鍵但沒有值dict2有鍵和值

dict2的值可以作為dict1中的鍵找到。 我正在嘗試編寫代碼來識別 dict2 中的哪些值與dict2中的鍵匹配。

我的嘗試注釋代碼如下。

dict1 = {('dict1_key1',): [], ('dict1_key2',): []} #dictionary with keys, but no values;


for i in dict2.keys():  #iterate through the keys of dict2
    for x in dict2[i]:  #reaching every element in tuples in dict2
        if x == dict1.keys():  #if match found in the name of keys in dict1
            print(f"{i} holding {x}.") #print which key and value pair in dict 2 match the keys in dict1

如果我按如下方式編寫for loop ，則代碼有效：

for i in dict2.keys():  #iterate through the keys of dict2
    for x in dict2[i]:  #reaching every element in tuples in dict2
        if x == dict1_key1 or x == dict1_key2():  #if match found in the name of keys in dict1
            print(f"{i} holding {x}.") #print which key and value pair in dict 2 match the keys in dict1

但是，實際上dict1需要能夠包含不同數量的鍵，這就是為什么我希望if x == dict1.keys():可以工作的原因。

任何反饋將不勝感激。

@馬克邁耶

根據要求的示例值：

dict1 = {('Tower_001',): [], ('Tower_002'): []}

dict2 = {1: 'Block_A', 'Tower_001'] #first key in dict2
        #skipping keys 2 through 13
        {14: ['Block_N', 'Tower_002']#last key in dict2

Answer 1

您可以設置dict1.keys和dict2.value中的所有值。 然后只需取這些集合的交集即可找到也是值的鍵：

dict1 = {('Tower_001',): [], ('Tower_005',): [], ('Tower_002',): []}

dict2 = {1: ['Block_A', 'Tower_001'], #first key in dict2
        14: ['Block_N', 'Tower_002']} #last key in dict2
         
         
set(k for l in dict2.values() for k in l) & set(k for l in dict1.keys() for k in l)
# {'Tower_001', 'Tower_002'}