[英]Sorting a Java String Array with a pattern
我目前正在讀取和寫入文本文件,但我想不出一種排序方式。 我以為我可以按模式排序。 我想按模式(0-9,AZ,az)對 java 字符串數組進行排序。 基本上我想忽略非字母數字字符,用字母前面的數字和小寫字母前面的大寫字母(即0-9、AZ、az)進行排序。 我想刪除只有非字母數字字符的行。
File f1 = new File(fp);
FileReader fr = new FileReader(f1);
BufferedReader br = new BufferedReader(fr);
List<String> lines = new ArrayList<String>();
String line;
while ((line = br.readLine()) != null) {
count++;
// SORT GOES HERE
if (line.contains(sx)) {
line = line.replace(line, "");
}
if (yint > 0 && !line.isBlank()) {
line = line.substring(yint);
}
if(!line.isBlank()){
line = line.replace(line, count + " " + line + "\n");
lines.add(line);
} else {
lines.add(line);
}
}
fr.close();
br.close();
FileWriter fw = new FileWriter(f1);
BufferedWriter out = new BufferedWriter(fw);
for(String s : lines)
out.write(s);
out.flush();
out.close();
我可能會在最后使用Collections.sort()
之類的東西,並在循環中進行簡單的檢查:
File f1 = new File(fp);
FileReader fr = new FileReader(f1);
BufferedReader br = new BufferedReader(fr);
List<String> lines = new ArrayList<String>();
String line;
while ((line = br.readLine()) != null) {
count++;
if (!line.matches("[a-zA-Z0-9]+")) {
continue;
}
if (line.contains(sx)) {
line = line.replace(line, "");
}
if (yint > 0 && !line.isBlank()) {
line = line.substring(yint);
}
if(!line.isBlank()){
line = line.replace(line, count + " " + line + "\n");
lines.add(line);
} else {
lines.add(line);
}
}
fr.close();
br.close();
Collections.sort(lines, (a, b) -> {
String aNum = a.replaceAll("[^a-zA-Z0-9]", "");
String bNum = b.replaceAll("[^a-zA-Z0-9]", "");
return a.compareTo(b);
});
FileWriter fw = new FileWriter(f1);
BufferedWriter out = new BufferedWriter(fw);
for(String s : lines)
out.write(s);
out.flush();
out.close();
編輯:您當然可以通過快速檢查排序等方式使這項工作更快/更好 - 但通常這是我認為的想法
您在閱讀文件時無法對文件進行排序,在您的情況下需要先完成:
// Sort the file
Path initialFile = Paths.get("myFile.txt");
List<String> sortedLines = Files.lines(initialFile)
.sorted()
.collect(Collectors.toList());
// Process the sorted lines
List<String> lines = new ArrayList<String>();
int count=0;
for(String line : sortedLines) {
System.out.println("l: "+line);
count++;
if (line.contains(sx)) {
line = line.replace(line, "");
}
if (yint > 0 && !line.isEmpty()) {
line = line.substring(yint);
}
if (!line.isEmpty()) {
System.out.println("line:"+line);
line = line.replace(line, count + " " + line + "\n");
System.out.println("new line:"+line);
lines.add(line);
} else {
System.out.println("add:"+line);
lines.add(line);
}
}
// Write output file
File f1 = new File("myFile.txt");
try(BufferedWriter out = new BufferedWriter( new FileWriter(f1))){
for (String s : lines)
out.write(s);
}
嘗試這個。
static void sortByAlphaNumeric(String inFile, String outFile) throws IOException {
List<String> lines = Files.readAllLines(Paths.get(inFile)).stream()
.map(line -> new Object() {
String sortKey = line.replaceAll("[^0-9A-Za-z]", "");
String originalLine = line;
})
.filter(obj -> !obj.sortKey.equals(""))
.sorted(Comparator.comparing(obj -> obj.sortKey))
.map(obj -> obj.originalLine)
.collect(Collectors.toList());
Files.write(Paths.get(outFile), lines);
}
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