[英]How "struct" members are indexed? How to access them correctly in C?
“候選” stuct
如何在以下代碼中編制索引? 當我嘗試打印創建的結構的最后一個成員(最后一個索引?)時,它是 candidates["last index"].name 假設我確實有 4 個候選人,這將導致 candidate_count = argc - 1
等於 4,所以,我認為如果我通過索引 4 訪問第 4 個成員,我應該到達 null 終結符,對嗎? 但那沒有發生! 代碼看起來像這樣
(在程序末尾找到)
printf("Winner is %s", candidates[4].name);
它完美地打印了候選人姓名數組的第 4 個成員姓名? 那個怎么樣? 不應該像
printf("Winner is %s", candidates[3].name)
這是我寫的完整程序:
#include <cs50.h>
#include <stdio.h>
#include <string.h>
#include <ctype.h>
// Max number of candidates
#define MAX 9 // define MAX as a constant = 9 (or any number which might be used without '=' sign).
// define syntax won't allocate any memory for the constant 'MAX', it can be used later as int MAX
// which = int 9
// Candidates have name and vote count, stuct is the best to use to create a custom data type.
typedef struct
{
string name;
int votes;
}
candidate;
// Array of candidates
candidate candidates[MAX];
// Number of candidates as a global variable
int candidate_count;
// Function prototypes
bool vote(string name);
void print_winner(void);
int main(int argc, string argv[])
{
// Check for invalid usage, the args. must be more than 2, i.e 3 and up!
if (argc < 2)
{
printf("Usage: plurality [candidate ...]\n");
return 1;
}
// Populate array of candidates
candidate_count = argc - 1; // -1 because one argument is the program's name. the rest are the
// candidates' names.
if (candidate_count > MAX)
{
printf("Maximum number of candidates is %i\n", MAX);
return 2; // err code 2 means that the candidates number is exceeded
}
for (int i = 0; i < candidate_count; i++) // Store the candidates names from the argv[] into,
// the struct candidate of candidates.name[] array to be globally available.
{
candidates[i].name = argv[i + 1]; // +1 because the 0th index is the programs name.
candidates[i].votes = 0; // initializing 0 for all candidates
}
// Enter the number of people allowed to vote, in other words, total number of votes allowed.
int voter_count = get_int("Number of voters: ");
// Loop over all voters to enter their votes for a candidate of the available names.
for (int i = 0; i < voter_count; i++)
{
string name = get_string("Vote: ");
// Check for invalid vote
if (!vote(name)) // Use function vote(string name) to check for the presence,
//of the candidate's name.
{
printf("Invalid vote.\n");
}
}
// Display winner of election
print_winner(); // call this func. to print the winner's name.
}
// Update vote totals given a new vote
bool vote(string name)
{ // loop over all candidates names checking it's availability by comparing it to user-entered name.
// global variable candidate_count is used to keep track of number of candidates.
for (int i = 0; i < candidate_count ; i++)
{
if (strcmp (name, candidates[i].name) == 0)
{
// Update the candidate's vote count.
candidates[i].votes++; // update the votes count for the candidate indexed @ i.
return true;
}
} // End for() iteration over the candidates names indeces.
return false;
}
// Print the winner (or winners) of the election
void print_winner(void)
/*
Bubble sorting Algorithm;
- A pass is a number of steps where the adjacent elements are compared to eachother from left to right in
an int array each one with the one next to it.
- If an array has a number of elements of 5, so, n = 5.
- There will always be a maximum of n - 1 passes in bubble sorting
- There will be a maximum of n - 1 comparisons of items in each pass if code is not optimized
*/
{
int swap = 0; // A flag to check if swapping happened.
//( To check if the array is sorted, swap happening = not sorted yet else the array is sorted)
for (int i = 0; i <= candidate_count - 1; i++) // passes = n - 1 where n = number of elements to compare.
{
for (int j = 0; j <= candidate_count - 1 - i; j++) // Number of comparisions(elements to be checked -
// with thier adjacent ones) to be conducted in each pass, after pass the last element will always
// be the greatest element there for no need to compare it with the element before it. therefore,
// candidate_count - 1 - i where i value starting form 0 by the outer for loop reduces the number -
// of steps or elements to be checked each iteration
{
/* if the first candidate number of votes element in the array is Greater-Than the adjacent next
one, swap them and keep a flag or indicate that you did swap them.
*/
if ( candidates[j].votes > candidates[j + 1].votes)
{
// Swap the position of the struct candidates elements inside
candidate temp = candidates[j];
candidates[j] = candidates[j + 1];
candidates[j + 1] = temp;
swap = 1; // a flag to indicated the swapping actually happened.
} // End swapping if() statement.
}
if (swap == 0) // if no swapping happened
break;
}
/* When Populating array of candidates, candidate_count = argc - 1; // -1 because one argument
is the program's name. the rest are the candidates' names.
*/
printf("Winner is %s, candidate count = %d \n", candidates[candidate_count].name, candidate_count);
return;
}
從評論中復制:
如果我在終端中運行該程序並添加“printf”來打印從索引 0 到 5 開始的候選人姓名和選票,這就是我得到的:
c ~/pset3/plurality/ $ ./plurality moh zoz sos
Number of voters: 5
Vote: moh
Vote: moh
Vote: moh
Vote: zoz
Vote: sos
Winner is moh, candidate count = 3
The candidate name : (null) votes : 0
The candidate name : zoz votes : 1
The candidate name : sos votes : 1
The candidate name : moh votes : 3
The candidate name : (null) votes : 0
The candidate name : (null) votes : 0
解決方案只是從該行的條件中刪除“等於”:
for (int j = 0; j <= candidate_count - 1 - i; j++)
看起來像這樣
for (int j = 0; j < candidate_count - 1 - i; j++)
您的冒泡排序有錯誤。
第二個循環的條件是j <= candidate_count - 1 - i
但它應該是j <= candidate_count - 2 - i
。 這是因為您交換了j
和j+1
處的元素。 但是根據您的條件j == candidate_count - 1
這會導致candidate_count-1
和candidate_count
的交換。
要找到此類錯誤,您應該學習如何使用調試器或將 debug output 添加到您的程序中,例如
printf("swap(%d, %d)\n", j, j+1);
然后你可以更好地理解你的程序實際做了什么。
作為旁注: candidates
的排序不是必需的,因為您可以簡單地遍歷數組並搜索vote
最多的候選人,例如:
if (candidate_count < 1) {
// some error handling
} else {
candidate biggest = candidates[0];
for (int i = 1; i < candidate_count; i++) {
if (biggest.vote < candidates[i].vote) {
biggest = candidates[i];
}
}
// do what ever you want to do with the winner
}
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